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ycow [4]
3 years ago
15

A 0.40-m3 insulated piston-cylinder device initially contains 1.3 kg of air at 30°C. At this state, the piston is free to move.

Now air at 500 kPa and 70°C is allowed to enter the cylinder from a supply line until the volume increases by 50%. Using constant specific heats at room temperature, determine (a) the final temperature, (b) the amount of mass that has entered, and (d) the work done; and (d) entropy generation

Engineering
1 answer:
Setler79 [48]3 years ago
6 0

Answer:

(a) The Final Temperature is 315.25 K.

(b) The amount of mass that has entered  0.5742 Kg.

(c) The work done is 56.52 kJ.

(d) The entrophy generation is 0.0398 kJ/kgK.

Explanation:

Explanation is in the following attachments.

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MAXImum [283]

Answer:

The answer is c-voltage

5 0
3 years ago
A horizontal 2-m-diameter conduit is half filled with a liquid (SG=1.6 ) and is capped at both ends with plane vertical surfaces
luda_lava [24]

Answer:

Resultant force = 639 kN and it acts at 0.99m from the bottom of the conduit

Explanation:

The pressure is given as 200 KPa and the specific gravity of the liquid is 1.6.

The resultant force acting on the vertical plate, Ft, is equivalent to the sum of the resultant force as a result of pressurized air and resultant force due to oil, which will be taken as F1 and F2 respectively.

Therefore,

Ft = F1 + F2

According to Pascal's law which states that a change in pressure at any point in a confined incompressible fluid is transmitted throughout the fluid such that the same change occurs everywhere, the air pressure will act on the whole cap surface.

To get F1,

F1 = p x A

= p x (πr²)

Substituting values,

F1 = 200 x π x 1²

F1 = 628.32 kN

This resultant force acts at the center of the plate.

To get F2,

F2 = Π x hc x A

F2 = Π x (4r/3π) x (πr²/2)

Π - weight density of oil,

A - area on which oil pressure is acting,

hc - the distance between the axis of the conduit and the centroid of the semicircular area

Π = Specific gravity x 9.81 x 1000

Therefore

F2 = 1.6 x 9.81 x 1000 x (4(1)/3π) x (π(1)²/2)

F2 = 10.464 kN

Ft = F1 + F2

Ft = 628.32 + 10.464

Ft = 638.784 kN

The resultant force on the surface is 639 kN

Taking moments of the forces F1 and F2 about the centre,

Mo = Ft x y

Ft x y = (F1 x r) + F2(1 - 4r/3π)

Making y the subject,

y = (628.32 + 10.464(1 - 4/3π)/ 638.784

y = 0.993m

7 0
3 years ago
PLEASE HELP
Anna11 [10]
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A. Satellites that enter Earth’s atmosphere land mostly in the ocean.


B. NASA does a good job informing people of when satellites will enter the atmosphere.


C. Satellites that enter Earth’s atmosphere land mostly in unpopulated areas.


D. Much of a satellite is destroyed during the process of entering Earth’s atmosphere.
8 0
3 years ago
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Why is the lubrication system of an internal combustion engine equipped with an oil filter?
Ierofanga [76]

Answer:

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Some cars have an FCW, which stands for
Natalka [10]

Answer:

FCW in car stands for <em>Forward Collision Warning. </em>

<u>Explanation:</u>

The vehicle speed is monitored by <em>FCW system</em>, this is an advanced technology which indicates to the rear vehicle that a crash is going to happen if the vehicle gets close <em>because of speed</em>. This FCW systems monitor’s distance between the vehicles and speed of the vehicles.

<em>FCW system do not control the vehicle completely</em>. This system consists of sensors to detect stationary or slower-moving vehicles. A signal alerts the driver if the <em>distance between the vehicles is less</em> so that crash is being happened. It helps driver from crash by changing his route. Cars with this technology consists of audible alert.  

8 0
3 years ago
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