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Scorpion4ik [409]
3 years ago
15

What is on tenth less than 0.61

Mathematics
1 answer:
MatroZZZ [7]3 years ago
7 0

Answer:

0.6

Step-by-step explanation:

because 0.61= 1=0 so 0.6+0=0.6

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Two angles are supplementary. The measure of one angle is 4 more than 7 times the other angle. Find the measures of both angles.
mylen [45]

Answer:

<u>The smaller angle measures 44° and the larger measures 136°</u>

Step-by-step explanation:

Smaller angle = x

Larger angle = 3x + 4

Therefore, we have:

x + 3x + 4 = 180

4x = 180 - 4

4x = 176

x = 176/4

x = 44 ⇒ 3x + 4 = 136

The smaller angle measures 44° and the larger measures 136°

<u>Can I get a brainliest plz?</u>

6 0
4 years ago
Read 2 more answers
How do I answer this question pls help me
n200080 [17]

Answer:

  14.7 quarts

Step-by-step explanation:

Use the given equivalence figures to write a proportion. Solve the proportion for the unknown value.

__

  quarts/liters = x/14 = 1/0.95 . . . . . the conversion is given as 1 qt = 0.95 L

Multiply by 14 to find x.

  x = 14(1/0.95) ≈ 14.7

There are about 14.7 quarts in 14 liters.

_____

<em>Additional comment</em>

You are given a value in liters (14 liters) and asked for the equivalent in quarts. That means you want to change the units from liters to quarts. To do that, you can multiply the given value (14 liters) by a conversion factor that has quarts in the numerator and liters in the denominator. That is what the fraction 1/0.95 is in the above. You will note that units of liters cancel in this equation.

  (14\text{ liters})\times\dfrac{1\text{ quart}}{0.95\text{ liter}}=\dfrac{14}{0.95}\text{ quarts}\approx14.7\text{ quarts}

This rule, "use a conversion factor that divides by the units you don't want and multiplies by the units you do want" applies to any units conversion problem. The conversion factor you use should <em>always</em> have <em>equal quantities</em> in the numerator and denominator. (Here, the equal quantities are 1 quart and 0.95 liters.)

You will notice that we treat units just like any variable. They can be multiplied, divided, cancelled, raised to a power. Only terms with like units can be added or subtracted.

4 0
2 years ago
*PLEASE HELP ME* (math attachment) IT'S PAST MIDNIGHT I'M TIRED AND DESPERATE
Luda [366]
<h3><u>Answer:</u></h3>

D

<h3><u>Step-by-step explanation:</u></h3>

let's rewrite this

x + y = 11                  <em>- equation 1</em>

   - x = - y - 9           <em>- equation 2</em>

solve the first equation for x

x + y = 11            (add -y to both sides to get x by itself)

     x = -y + 11          <em> - equation 3</em>

now substitute -y + 11 for x in the second equation

 y - 11 = - y - 9        (2 negative signs next to each other equals positive)

2y - 11 = -9              (add y to both sides)

      2y = 2               (add 11 to both sides)

        y = 1                (divide both sides by 2)

now substitute y = 1 into equation 3

x = -1 + 11

x = 10

therefore, x = 10 and y = 1. in coordinates, x goes before y

therefore, the coordinates are (10, 1)

therefore the answer is D

good luck my friend! hope this helped a lot! also, i found a website if you don't fully understand this, its called MathPapa, i didn't use it to work this out so my working might be different but it definitely helps me sometimes. for an equation like this, type it likes this: x+y=11; -x=-y-9

-cheesetoasty

3 0
3 years ago
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A collection of coins contains a total of sixteen dimes and quarters. It is worth $2.20 in all. How many dimes are in the collec
grin007 [14]

9514 1404 393

Answer:

  12 dimes

Step-by-step explanation:

Let q represent the number of quarters. Then the number of dimes is 16-q and the total value is ...

  0.25q +0.10(16 -q) = 2.20

  0.15q +1.60 = 2.20 . . . . . . . simplify

  0.15q = 0.60 . . . . . . . . subtract 1.60

  q = 4 . . . . . . . . . . . divide by 0.15

  16-q = 12

There are 12 dimes in the collection.

5 0
3 years ago
Determine if the set of ordered pairs is a relation or a function.
MariettaO [177]

Answer:

Function

Step-by-step explanation:

Since there is once variable of y for ever6y value of x in (-1,2), (-2,1), (-3,0), (-4,-1), this relation is a function.

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3 years ago
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