Answer:
The correct answer is 0.047 mol/L
Explanation:
The atmospheric air is a mixture of gases. We can assume an ideal behavior of the gas and use the ideal gas equation:
PV= nRT
where P is the pressure, V is the volume, n is the number of moles, R is a constant (0.082 L.atm/K.mol) and T is the temperature in K.
We have to first convert the pressure from Torr to atm:
760 Torr= 1 atm
⇒ 718 Torr x 1 atm/760 Torr = 0.945 atm
Then, we convert the temperature from ºC to K:
0ºC = 273 K
⇒ -29ºC+273= 244 K
Finally, we introduce the data in the equation and calculate de densitiy, which is the moles per liters of gas (n/V):
PV = nRT
n/V= P/RT
n/V = (0.945 atm)/(0.082 L.atm/K.mol x 244 K) = 0.047 mol/L
Answer:
One of each
Explanation:
Be is in Group 2, so it loses its two valence electrons in a reaction to form Be²⁺ ions.
Carbonate ion has the formula CO₃²⁻.
We can use the criss-cross method to work out the formula of beryllium carbonate.
The steps are
Write the symbols of the anion and cation.
Criss-cross the numbers of the charges to become the subscripts of the other ion.
Write the formula with the new subscripts.
Divide the subscripts by their highest common factor.
Omit all subscripts that are 1.
When you use this method with Be²⁺ and CO₃²⁻, you might be tempted to write the formula for the beryllium carbonate as Be₂(CO₃)₂
However, you can divide the subscripts by their largest common factor (2).
This gives you the formula Be₁(CO₃)₁.
We omit subscripts that are 1, so the correct formula is
BeCO₃
There is one Be²⁺ ion and one CO₃²⁻ ion in a formula unit of beryllium carbonate.
The molar mass of the following compounds in two decimal places are as follows:
- NH3: 17.04 g/mol
- Mg(OH)2: 58.33 g/mol
- Fe2O3: 159.70 g/mol
<h3>MOLAR MASS:</h3>
The molar mass of a compound is the sum of all the atomic masses of the elements that constitutes the compound.
According to this question, three compounds were given as follows: NH3, Mg(OH)2 and Fe2O3.
The atomic mass of the elements in this compounds are as follows:
- N = 14
- H = 1
- Mg = 24
- O = 16
- Fe = 56
- The molar mass of NH3 = 14 + 3 = 17g/mol
- The molar mass of Mg(OH)2 = 24 + 32 + 2 = 58g/mol
- The molar mass of Fe2O3 = 56(2) + 16(3) = 160g/mol
Learn more about molar mass at: brainly.com/question/12127540
Answer:
9.9 moles of Ag₂S contain 9.9 moles of sulfur.
Explanation:
Given data:
Number of moles of Ag₂S = 9.9 mol
Number of moles of Sulfur = ?
Solution:
One mole of Ag₂S having 1 mole of sulfur.
In 9.9 moles:
9.9 moles × 1 = 9.9 moles
So 9.9 moles of Ag₂S contain 9.9 moles of sulfur.
