2NO + O₂ = 2NO₂
V(O₂)=10.5 L
V(NO₂)=2V(O₂)
V(NO₂)=2*10.5=21.0 L
21.0 liters of NO2 are produced
Explanation:
It is necessary that the glassware which we use during titration needs to be clean and dry before use because otherwise the remaining reagents will get mixed up with the solutions.
As a result, this will lead to a change in analysis results.
Hence, an error will occur in the resulting values.
Also, when not cleaned properly the any other substance remaining in the glassware might react with the solution leading to a change in the solution.
In that case also, error will occur.
Answer:
V₂ = 1.92 L
Explanation:
Given data:
Initial volume = 0.500 L
Initial pressure =2911 mmHg (2911/760 = 3.83 atm)
Initial temperature = 0 °C (0 +273 = 273 K)
Final temperature = 273 K
Final volume = ?
Final pressure = 1 atm
Solution:
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
by putting values,
V₂ = P₁V₁ T₂/ T₁ P₂
V₂ = 3.83 atm × 0.500 L × 273 K / 273 K × 1 atm
V₂ = 522.795 atm .L. K / 273 K.atm
V₂ = 1.92 L
Answer: Option (B) is the correct answer.
Explanation:
Whenever there is less concentration of solute particles in a solvent then it means less number of solute particles are available. As a result, there will occur less number of collisions between the solvent and solute particles.
It means that there will be a decrease in rate of reaction.
But if there is more concentration of solute particles then it shows more number of solute particles are available for reaction. As a result, more number of collisions will take place between the particles of solute and solvent.
Hence, then there will occur an increase in rate of reaction.
Thus, we can conclude that a lower concentration of dissolved particles decrease the reaction rate because when there are less dissolved particles, less collisions take place.