Question

Predict what precipitate will be formed using the solubility rules. then write the net ionic equation for the formation of the solid. balance the net equation.
CaCl2(aq) + K3PO4(aq)

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i’ve already got a majority of the net ionic equation, CaPO4(aq) + Cl2K3(aq) = ?
but i don’t know what the solid will end up being

Answer 1

Answer: The net ionic equation for the following precipitation reaction will be $3Ca^{2+}(aq.)+2PO_4^{3-}(aq.)\rightarrow Ca_3(PO_4)_2(s)$

Explanation:

Precipitation reaction is defined as the reaction in which two soluble salts combine in aqueous state to form one insoluble product known as a precipitate.

For the reaction of calcium chloride and potassium phosphate, the reaction follows:

$3CaCl_2(aq.)+2K_3PO_4(aq.)\rightarrow Ca_3(PO_4)_2(s)+6KCl(aq.)$

The ionic equation for the above reaction follows:

$3Ca^{2+}(aq.)+6Cl^-(aq.)+6K^+(aq.)+2PO_4^{3-}(aq.)\rightarrow Ca_3PO_4(s)+6K^+(aq.)+6Cl^-(aq.)$

To write the net ionic equation, spectator ions are not written because these ions lie on both the sides of the reaction and does not affect equilibrium. These ions are ignored in writing the net ionic equation.

Hence, the net ionic equation becomes:

$3Ca^{2+}(aq.)+2PO_4^{3-}(aq.)\rightarrow Ca_3(PO_4)_2(s)$