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tangare [24]
3 years ago
15

the slope of the line below is -5. which of the following is the point slope of the line? y intercept = (2, -8)

Mathematics
1 answer:
umka2103 [35]3 years ago
3 0

Answer:

Step-by-step explanation:

The y-intercept cannot be (2,-8). The x-coordinate of the y-intercept is 0.

Point-slope equation for line of slope -5 that passes through (2,-8):

y+8 = -5(x-2)

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Based on past experience, the main printer in a university computer centre is operating properly 90% of the time. Suppose inspec
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Answer:

a) 38.74% probability that the main printer is operating properly for exactly 9 inspections.

b) Approximately 100% probability that the main printer is operating properly for at least 3 inspections.

c) The expected number of inspections in which the main printer is operating properly is 9.

Step-by-step explanation:

For each inspection, there are only two possible outcomes. Either it is operating correctly, or it is not. The probability of the printer operating correctly for an inspection is independent of any other inspection, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Based on past experience, the main printer in a university computer centre is operating properly 90% of the time.

This means that p = 0.9

Suppose inspections are made at 10 randomly selected times.

This means that n = 10

A) What is the probability that the main printer is operating properly for exactly 9 inspections.

This is P(X = 9). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 9) = C_{10,9}.(0.9)^{9}.(0.1)^{1} = 0.3874

38.74% probability that the main printer is operating properly for exactly 9 inspections.

B) What is the probability that the main printer is operating properly for at least 3 inspections?

This is:

P(X \geq 3) = 1 - P(X < 3)

In which

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)

So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}.(0.9)^{0}.(0.1)^{10} \approx 0

P(X = 1) = C_{10,1}.(0.9)^{1}.(0.1)^{9} \approx 0

P(X = 2) = C_{10,2}.(0.9)^{2}.(0.1)^{8} \approx 0

Thus:

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0 + 0 + 0 = 0

Then:

P(X \geq 3) = 1 - P(X < 3) = 1 - 0 = 1

Approximately 100% probability that the main printer is operating properly for at least 3 inspections.

C) What is the expected number of inspections in which the main printer is operating properly?

The expected value for the binomial distribution is given by:

E(X) = np

In this question:

E(X) = 10(0.9) = 9

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Answer:

yes

Step-by-step explanation:

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Answer:

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i.e. no of houses which need new windows = 15*7%\\=1.05

If there are total 100 houses, 1.05 houses require a new window

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= 0.0105

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Answer:

The line of best fit would be the line in between all the points in the scatter plot that is the closest to having an equal amount of dots on each side.

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