Answer: The initial investment would be Rs. 25243.41.
Step-by-step explanation:
Since we have given that
Amount = $70000
Rate of interest = 6%
Time period = 17 years
So, we need to find the initial investment.
Using "compound interest continuously", we get that :
Hence, the initial investment would be Rs. 25243.41.
I believe it is 15 I am using trigonometry but I’m not 100% sure
Answer:
The container can hold 18 gallons
Step-by-step explanation:
Assume the container can hold x gallons
∵ The container is full with water
∵ It can hold x gallons
→ Multiply by x to find the number of gallons in the container
∴ The number of gallons in the container = x
∵ 4 gallons of water pouring out
∵ It is full
→ Multiply by x to find the number of gallons left in it
∴ The number of gallons left in the container = x
→ The difference between the numbers of gallons is 4 gallons
∵ x - x = 4
→ Subtract the terms of the left side
∴ x = 4
→ Multiply both sides by 9
∴ 2x = 36
→ Divide both sides by 18
∴ x = 18
∵ x represents the full of the container
∴ The container can hold 18 gallons
Answer:
f(x)
Step-by-step explanation:
f(x)=x-1/x+5
y=x-1/x+5
xy+5y=x-1
xy-x=-1-5y
x(y-1)=1-5y
x=-1-5y/y-1
x=-5
Answer:
- inverse is not a function
- unless the domain is restricted to |x| ≥ 1.2 (approximately)
Step-by-step explanation:
The test to see if the inverse function is also a function is called the "horizontal line test." The test passes if any horizontal line intersects the graph in only one place.
Here, a horizontal line can intersect the graph in 1, 2, or 3 places, so the test fails. The function does not have an inverse that is a function.
__
If the domain of the inverse relation is restricted to |x| > 1.2, then that inverse will map any x to only a single value of y. Then it will be a function.
_____
The graph shows the original function (dashed red line) and the inverse relation (blue). The green shading marks values of x for which there is a single value of y, so the inverse relation is a function in those regions.
(We could be more specific as to the limits on the domain of f^-1(x), but the given graph seems to have an unknown vertical scale factor.)