The two numbers are 30 and 11
<em><u>Solution:</u></em>
Given that we have to separate the number 41 into two parts
Let the second number be "x"
<em><u>Given that first number is eight more than twice the second number</u></em>
first number = eight more than twice the second number
first number = 8 + twice the "x"
first number = 8 + 2x
So we can say first number added with second number ends up in 41
first number + second number = 41
8 + 2x + x = 41
8 + 3x = 41
3x = 41 - 8
3x = 33
x = 11
first number = 8 + 2x = 8 + 2(11) = 8 + 22 = 30
Thus the two numbers are 30 and 11
Do the parentheses first
Since it’s dividing you are supposed to times it
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20 total
6 have average of 5 years
6 x 5 = 30
20-6 = 14
14 have average of 8 years
14 x 8 = 112
112 + 30 = 142
142 / 20 = 7.1 years
Answer:
Option A is the correct answer.
Explanation:
The given pyramid has 3 lateral triangular side as shown below.
Base of triangle = 12 unit
We need to find perpendicular.
By Pythagoras theorem we have
Perpendicular² = 10²-6²
Perpendicular = 8 unit
So area of 1 lateral triangle = 1/2 x Base x Perpendicular.
= 1/2 x 12 x 8 = 48 unit²
Area of lateral side = 3 x 48 = 144 unit²
Option A is the correct answer.