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Anna35 [415]
3 years ago
12

What is the simplified form of the difference shown below? (3a^2-6a-1)-(5a^2-2a+3)

Mathematics
1 answer:
kodGreya [7K]3 years ago
8 0

Answer:

(3a^2-6a-1)-(5a^2-2a+3)

= 3a²-6a-1 -5a²+2a-3

=3a²-5a²-6a+2a-1-3

= -2a²-4a-4

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Answer:

\frac{dy}{dx} = \frac{4}{1-x}

Step-by-step explanation:

    y = 3 - 4ln(1 - x)

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⇒ \frac{dy}{dx} =0 -4ln(1-x)\frac{d}{dx}

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FInd the surface area of the triangular prism
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Answer:

273.7

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4 years ago
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Tanner collected 360 cans and bottles while fundraising for his baseball team. This was 40% of what Reggie collected. How many c
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work for a publishing company. The company wants to send two employees to a statistics conference. To be​ fair, the company deci
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Answer:

(a) S = {MR, MJ, MD, MC, RJ, RD, RC, JD, JC, DC}

(b) The probability that Roberto and John attend the​ conference is 0.10.

(c) The probability that Clarice attends the​ conference is 0.40.

(d) The probability that John stays​ home is 0.60.

Step-by-step explanation:

It is provided that :

Marco (<em>M</em>), Roberto (<em>R</em>), John (<em>J</em>), Dominique (<em>D</em>) and Clarice (<em>C</em>) works for the company.

The company selects two employees randomly to attend a statistics conference.

(a)

There are 5 employees from which the company has to select two employees to send to the conference.

So the total number of ways to select two employees is:

{5\choose 2}=\frac{5!}{2!(5-2)!}=\frac{5\times 4\times 3!}{2\times 3!}=10

The 10 possible samples are:

MR, MJ, MD, MC, RJ, RD, RC, JD, JC, DC

(b)

The probability of the event <em>E</em> is:

P(E)=\frac{n(E)}{N}

Here,

n (E) = favorable outcomes

N = Total number of outcomes.

The variable representing the selection of  Roberto and John is, <em>RJ</em>.

The favorable number of outcomes to select Roberto and John is, 1.

The total number of outcomes to select 2 employees is 10.

Compute the probability that Roberto and John attend the​ conference as follows:

P(RJ)=\frac{n(RJ)}{N}=\frac{1}{10}=0.10

Thus, the probability that Roberto and John attend the​ conference is 0.10.

(c)

The favorable outcomes of the event where Clarice attends the conference are:

n (C) = {MC, RC, JC and DC} = 4

Compute the probability that Clarice attends the​ conference as follows:

P(C)=\frac{n(C)}{N}=\frac{4}{10}=0.40

Thus, the probability that Clarice attends the​ conference is 0.40.

(d)

The favorable outcomes of the event where John does not attends the conference are:

n (J') = MR, MD, MC, RD, RC, DC

Compute the probability that John stays​ home as follows:

P(J')=\frac{n(J')}{N}=\frac{6}{10}=0.60

Thus, the probability that John stays​ home is 0.60.

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