1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
SIZIF [17.4K]
3 years ago
13

a group of fitness club members lose a combined total of 28 kilograms in 1 week. there are approximately 2.2 pounds in 1 kilogra

m. assuming the weight loss happened ar a constant rate, about how many pounds did the group lose each day
Mathematics
1 answer:
olga55 [171]3 years ago
6 0
The group lose 8.8 pounds per day. For a detailed calculation, please refer to the attachment.
Download docx
You might be interested in
Function help please
Korvikt [17]

Answer:

The first table represents a function.

Step-by-step explanation:

For it to be a function, there needs to be 1 unique y value of 1 unique x value.

  • Looking at 2nd table, we see x value of -5 is mapped to 2 different y values of -5 and 5. So this is not a function.
  • Looking at 3rd table, we see x value of -2 is mapped to 2 different y values of 2 and 4. So this is not a function.
  • Looking at 4th table, we see x value of -4 is mapped to 2 different y values of 2 and 0. So this is not a function as well.

Looking at table 1, there are no duplicate x values and each of the 4 x values map to different values. So the first table represents a function.

4 0
3 years ago
One alloy is 2 parts iron to 3 parts silver and another alloy is 7 parts iron to 3 parts silver. How much of each should be comb
Shalnov [3]
Let x be your first alloy
2/5x+7/10(30-x)=1/2(30)
4x+210-7x=150
3x=60
x=20
So, you need 20 lbs of the first alloy, and 10 parts of the second to make 30 lbs of half iron and half silver alloy!
8 0
3 years ago
Consider this linear function:
ivanzaharov [21]

Answer:

(-8,-3)

(-4,-1)

(0,1)

(2,2)

(6,4)

Step-by-step explanation:

One by one, substitue the x values and solve for y

3 0
2 years ago
The lifetime of a machine part has a continuous distribution on the interval​ (0, 50​) with probability density function​ f, whe
Strike441 [17]

Answer:

Probability that the lifetime of the machine part is less than 13 = 0.6782

Step-by-step explanation:

given that f(x)=(10+x)^{-2}

Normalizing the function we get

\int_{0 }^{50}cf(x)dx=1

\int_{0 }^{50}c(10+x)^{-2}dx=1

\therefore a=\frac{1}{\int_{0 }^{50}(10+x)^{-2}dx}

\therefore a=12

P(x< 13)=\int_{0}^{13}12(10+x)^{-2}dx\\\\P(X< 13)=0.6782

4 0
3 years ago
Math To Do, i-Ready X G isabella belongs to a fitness club X + student/dashboard/home sabella belongs to a fitness club. She pai
skad [1K]

Answer: 19 months

Step-by-step explanation:

given data:

amount paid initially when joining the club = $50.

monthly payments made = $10.

total amount paid since joining the club = $240.

Solution:

= 10X + 50 = 240

collect like terms

= 10X = 240 – 50

10X = 190

divide both sides by 10

10X/10 = 190/10

X = 19

isabella has been a member of the club for 19 months.

7 0
3 years ago
Other questions:
  • What is the correct reason for statement 2? Prove: 10(w + 6) + 4 = 10w + 64 Statements Reasons 1. 10(w + 6) + 4 1. Given 2. (10w
    13·1 answer
  • Factor the equation<br> <img src="https://tex.z-dn.net/?f=%208a%5E%7B8%7D%20-%2019a%7B7%7D%20%2B%2027a%7B2%7D" id="TexFormula1"
    9·1 answer
  • When h has the value of 4 calculate 26-4h
    14·2 answers
  • Find the domain and range of the relation and determine whether it is a function.
    12·1 answer
  • Grace is preparing grab bags for her stores open house she has 24 candles 16 pens and 40 figures each grab bag will be the same
    10·1 answer
  • 1.
    9·1 answer
  • Find the perimeter. Simplify your answer.
    7·1 answer
  • Can someone please help me with this easy math problem
    10·1 answer
  • Solve the system of equations 4x + 3y = 3 and y = 2x + 6.
    6·1 answer
  • If 2/3x − 1 = 4, then x=
    7·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!