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Darina [25.2K]
3 years ago
5

2) Ariel dropped a golf ball from her second story window. The ball starts from rest and hits the sidewalk 1.5 s later with a ve

locity of 14.7 m/s. Find the average acceleration of the golf ball.1.5x14.7 =22.05
Physics
1 answer:
Sergio [31]3 years ago
8 0

Answer:

Acceleration = 9.8m/s²

Explanation:

Given the following data;

Initial velocity = 0m/s (since it's starting from rest).

Final velocity, v = 14.7m/s

Time, t = 1.5 seconds.

To find acceleration;

In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.

This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time.

Hence, if we subtract the initial velocity from the final velocity and divide that by the time, we can calculate an object’s acceleration.

Mathematically, acceleration is given by the equation;

Acceleration (a) = \frac{final \; velocity  -  initial \; velocity}{time}

Acceleration = \frac{v  -  u}{t}

Substituting into the equation, we have;

Acceleration = \frac{14.7  -  0}{1.5}

Acceleration = \frac{14.7}{1.5}

Acceleration = 9.8m/s²

Therefore, the average acceleration of the golf ball is 9.8m/s².

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The radioactive element radium (Ra) decays by a process known asalpha decay,in which the nucleus emits a helium nucleus. (Factoi
tamaranim1 [39]

<u>Answer:</u> The energy released in the decay process is 4.6800\times 10^{11}J

<u>Explanation:</u>

The equation for the alpha decay of Ra-226 follows:

_{88}^{226}\textrm{Ra}\rightarrow _{2}^{4}\textrm{He}+_{86}^{222}\textrm{Rn}

To calculate the mass defect, we use the equation:

Mass defect = Sum of mass of product - Sum of mass of reactant

\Delta m=(m_{Rn}+m_{He})-(m_{Ra})

We know that:

m_{Rn}=222.0176u\\m_{Ra}=226.0254u\\m_{He}=4.0026u

Putting values in above equation, we get:

\Delta m=(222.0176+4.0026)-(226.0254)=-0.0052g=-5.2\times 10^{-6}kg

(Conversion factor: 1 kg = 1000 g )

To calculate the energy released, we use Einstein equation, which is:

E=\Delta mc^2

E=(-5.2\times 10^{-6}kg)\times (3\times 10^8m/s)^2

E=-4.6800\times 10^{11}J

Hence, the energy released in the decay process is 4.6800\times 10^{11}J

8 0
3 years ago
How many milliliters of water at 25.0°C with a density of 0.997 g/mL must be mixed with 162 mL of coffee at 94.6°C so that the r
Andre45 [30]

Answer:

The volume of water is 139 mL.

Explanation:

Due to the Law of conservation of energy, the heat lost by coffee is equal to the heat gained by the water, that is, the sum of heats is equal to zero.

Q_{coffee} + Q_{water} = 0\\Q_{coffee} = - Q_{water}

The heat (Q) can be calculated using the following expression:

Q=c \times m \times \Delta T

where,

c is the specific heat of each substance

m is the mass of each substance

ΔT is the difference in temperature for each substance

The mass of coffee is:

162mL.\frac{0.997g}{mL} = 162g

Then,

Q_{coffee} = - Q_{water}\\c_{c} \times m_{c} \times \Delta T_{c} = -c_{w} \times m_{w} \times \Delta T_{w}\\m_{c} \times \Delta T_{c} = -m_{w} \times \Delta T_{w}\\m_{w} = \frac{m_{c} \times \Delta T_{c}}{-\Delta T_{w}} \\m_{w}=\frac{162g \times (62.5 \°C - 94.6 \°C ) }{-(62.5 \°C - 25.0 \°C)} \\m_{w} = 139 g

The volume of water is:

139g.\frac{1mL}{0.997g} =139mL

7 0
4 years ago
How far does a car go in 30 seconds at a speed of 29 m/s? (The equation for<br> distance is d = st.)
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d = speed x time

distance = 29 x 30

distance = 870m

please mark as BRAINLIEST

8 0
2 years ago
Need help with number 6 and 7 please
elena-14-01-66 [18.8K]

358 rocks, critical thinking

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3 years ago
Arm circles are an effective dynamic stretch for swimmers because they raise blood pressure and improve muscle stamina lower bod
dybincka [34]

Answer : Option C) copy the movements performed during the activity.

Explanation : Arm circles are an effective dynamic stretch for swimmers because they copy the movements performed during the activity.

During swimming when the arm circles are performed it stretches the triceps brachii, loosens the shoulder blade and stretches the side muscles.

Often many people are observed to perform this arm circles stretch without bringing the elbow behind the head, but especially for swimmers, this increases the stretching length and reduces stress while swimming.

8 0
3 years ago
Read 2 more answers
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