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Aleksandr [31]
3 years ago
14

A cart rolling at ground level has K = 1500 J. It comes to a ramp, rolls up the ramp to an elevated platform. When it's on this

elevated platform, it has K = 1000 J. What does its gravitational potential energy equal on top of that platform?
Physics
1 answer:
Black_prince [1.1K]3 years ago
8 0
The potential energy Wood be 1000
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What's faster a slow car or a fast feather?​
krok68 [10]

Answer:

A fast feather

Explanation:

The faster any item is, the more momentum it has

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3 years ago
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peach pie in a 9.00 in diameter plate is placed upon a rotating tray. Then, the tray is rotated such that the rim of the pie pla
zavuch27 [327]

Explanation:

It is given that,

Diameter of the peach pie, d = 9 inches

Radius of the pie, r = 4.5 inches

The tray is rotated such that the rim of the pie plate moves through a distance of 183 inches, d = 183 inches

Let \theta is the angular distance that the pie plate has moved through.

It is given by :

\theta=\dfrac{d}{r}

\theta=\dfrac{183}{4.5}  

\theta=40.66\ radian

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\theta=6.47124\ revolution

Hence, this is the required solution.

5 0
3 years ago
An unbalanced force of 500 N is applied to a 75 kg object. What is the acceleration of the object?
NemiM [27]

1. Define Newtons second law of motion (this will help put things into perspective)

2.Get the mass of the object (in this case 75 kg)

3.The net force acting on the object...find it (in this case 500 N)

4.Change the equation to F=ma (500=75a)

5.Divide both sides by 75 and that is the acceleration.

7 0
3 years ago
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(a) Calculate the acceleration due to gravity on the surface of the Sun.
Ira Lisetskai [31]
<h2>a)Acceleration due to gravity on the surface of the Sun is 274.21 m/s²</h2><h2>b) Factor of increase in weight is 27.95</h2>

Explanation:

a) Acceleration due to gravity

                      g=\frac{GM}{r^2}

 Here we need to find acceleration due to gravity of Sun,

                G = 6.67259 x 10⁻¹¹ N m²/kg²

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    Radius of sun, r = 6.957 x 10⁸ m

Substituting,

                g=\frac{6.67259\times 10^{-11}\times 1.989\times 10^{30}}{(6.957\times 10^8)^2}\\\\g=274.21m/s^2

Acceleration due to gravity on the surface of the Sun = 274.21 m/s²

b) Acceleration due to gravity in earth = 9.81 m/s²

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8 0
3 years ago
Estimate the total number of bacteria and other prokaryotes in the biosphere of the earth. (assume the bacteria are found to a d
Fofino [41]
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Thus, the total amount of bacteria is:

2×10²² mm³ * 100 bacteria/1 mm³ = 2×10²⁴ bacteria
7 0
4 years ago
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