A good baseball pitcher can throw a baseball toward home plate at 85 mi/h with a spin of 1900 rev/min. How many revolutions does
1 answer:
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The car can travel 220.27 ft in 4.61 s of time.
Given that a sports car accelerates from a standing start to 65 mi/hr.
So the initial velocity = 0 ft/s
The final velocity = 65 mi/hr.
We convert the final velocity from mi/hr. to ft/s.
1 mi/hr = 5280/3600 ft/s
= 1.47 ft/s
Therefore final velocity = 65 x 1.47 = 95.55 ft/s
The time taken by the car = 4.61 s
Now the average acceleration of the car = final velocity - initial velocity / time taken = 95.55 - 0/ 4.61 s = 20.73
The displacement of the car , ,
where u is the initial velocity of the car, t, the time taken by the car and a, the average acceleration.
So, displacement = 0 x 4.61 + 1/2 x 20.73 x
= 220.27 ft
Hence the distance travelled by the sports car in 4.61s is 220.27 ft.
Learn more about the displacement at brainly.com/question/17006213
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Answer:
Explanation:
Magnetic field due to a moving charge
B = μ₀ / 4π x (qv x r)/r²
Given
B = .3 X 10⁻⁶ T,
r = 60 x 10⁻³ m
Putting these values in the given equation
.3 x 10⁻⁶ = 10⁻⁷ x qvsinθ /( 60 x 10⁻³)²
θ = 90 °
qv = 10.8 x 10⁻³
At point P
Sinθ = 60 / 72
r² = 72 x 72 x 10⁻⁶
B =
= 0.17 μT