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borishaifa [10]
3 years ago
15

Which car is harder to stop and why?

Physics
2 answers:
kondor19780726 [428]3 years ago
8 0

Answer:

The momentum of bath cars is 40000 Ns which make the difficulty to stop each car in aspect of fprce is the same.

Explanation:

Momentum (P) =mass(m) × velocity (v)

For car A,

                    P = m × v = 1000 × 40 = 40000 Ns

For car B,

                    P = m × v = 4000 × 10 = 40000 Ns

Force (F) = Momentum change(ΔΡ)/ time taken(t)

            F = ΔΡ/t

When stopping the car the momentum changes from 40000 Ns to 0

So momentum change in both cars is the same. So to stop the two cars in a  given time (t) you need the same force, which means you will feel same difficulty.

             

Bond [772]3 years ago
8 0

Answer:

The third option

Explanation:

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Answer:

a) Fi = 85.76 N

b) Fi = 87.8 N

Explanation:

Given:-

- Density of hydraulic oil, ρ = 804 kg/m^3

- The radius of input piston, ri = 0.00861 m

- The radius of output piston, ro = 0.141 m

Find:-

What input force F is needed to support the 23000-N combined weight of a car and the output plunger, when

(a) the bottom surfaces of the piston and plunger are at the same level

(b) the bottom surface of the output plunger is 1.10 m above that of the input plunger?

Solution:-

For part a.

- We see that both plungers are equal levels or there is no pressure due to elevation head. So we are only dealing with static pressure exerted by the hydraulic oil on both plungers to be equal. This part is an application of Pascal's Law:

                                  Pi = Po

                                  Fi / Ai = Fo / Ao

                                  Fi = Ai / Ao * Fo

                                  Fi = (ri/ro)^2 * Fo

                                  Fi = ( 0.00861 / 0.141 )^2 * 23000

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For part b.

- We see that both plungers are at different levels so there is pressure due to elevation head. So we are only dealing with static pressure exerted by the hydraulic oil on both plungers plus the differential in heads. This part is an application of Bernoulli's Equation:

                                  Pi = Po + ρ*g*h

Where,                     h = Elevation head = 1.10m

                                  Fi = (ri/ro)^2 * Fo + ρ*g*h*π*ri^2

                                  Fi = 85.76 + (804*9.81*1.1*3.142*0.00861^2)

                                  Fi = 87.8 N

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