Answer: 1896.55J/kg°C
Explanation:
The quantity of Heat Energy (Q) required to heat a material depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)
Thus, Q = MCΦ
Since,
Q = 1320 joules
Mass of material = 5.61kg
C = ? (let unknown value be Z)
Φ = 0.124°C
Then, Q = MCΦ
1320J = 5.61kg x Z x 0.124°C
1320J = 0.696kg°C x Z
Z = (1320J / 0.696kg°C)
Z = 1896.55 J/kg°C
Thus, the specific heat of the material is 1896.55J/kg°C
Answer: The diameter of the circular path is 2.96m
Explanation: centripetal acceleration = tangential speed^2 / radius of the circular path.
Centripetal acceleration = 2.7m/s^2
Tangential speed = 2.0m/s
Radius = 2.0^2 / 2.7 = 4/2.7
= 1.48m
Diameter = radius*2
= 1.48*2 = 2.96m.
Answer:
mass is 6.97 pounds
Explanation:
given data
volume = 3.1 liters
density = 1.020 g/ml = 1.02 kg/l
to find out
How many pounds of blood plasma
solution
we know mass formula from density that is
density = mass / volume
so
mass = density × volume ...............1
so put all value to get mass
mass = 1.02 × 3.1
mass = 3.162 kg
mass = 3.162 × 2.205 pounds
so mass is 6.97 pounds
