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Paladinen [302]
3 years ago
5

Please answer Will give brainlst

Mathematics
1 answer:
Debora [2.8K]3 years ago
3 0

Answer:

C or D In a chemical change, the atoms in the reactants rearrange themselves and bond together differently to form one or more new products with different characteristics than the reactants. When a new substance is formed, the change is called a chemical change.

Step-by-step explanation:

hope this helps have a good rest of your night :) ❤

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From what I am looking at, it seems as if it is. :)
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Whats the ninth term of 25 20 15 10 5
Kaylis [27]

Given:

The sequence is 25, 20, 15, 10, 5.

To find:

The ninth term of the given sequence.

Solution:

We have,

25, 20, 15, 10, 5

It is an AP because the difference between two consecutive terms are same.

Here,

First term (a) = 25

Common difference (d) = 20-25

                                       = -5

The nth terms of an AP is

a_n=a+(n-1)d

Where, a is the first term and d is the common difference.

Putting a=25, n=9 and d=-5 to get the 9th term.

a_9=25+(9-1)(-5)

a_9=25+(8)(-5)

a_9=25-40

a_9=-15

Therefore, the ninth term of the given sequence is -15.

3 0
2 years ago
Guys help me this is hard​
Leokris [45]

Answer:

well 126/9=14 but is the other stuff factor families or something? like whats the question asking

Step-by-step explanation:

5 0
3 years ago
What is the greatest possible error for 0.224m
Citrus2011 [14]

Answer:

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Step-by-step explanation:

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F(x) = 4√(2x³-1)<br> F'(x) =.....?
goldfiish [28.3K]

Answer:

\large\boxed{f'(x)=\dfrac{12x^2}{\sqrt{2x^3-1}}}

Step-by-step explanation:

f(x)=4\sqrt{2x^3-1}=4\left(2x^3-1\right)^\frac{1}{2}\\\\f'(x)=4\cdot\dfrac{1}{2}(2x^3-1)^{-\frac{1}{2}}\cdot3\cdot2x^2=\dfrac{12x^2}{(2x^3-1)^\frac{1}{2}}=\dfrac{12x^2}{\sqrt{2x^3-1}}\\\\\text{used}\\\\\sqrt{a}=a^\frac{1}{2}\\\\\bigg[f\left(g(x)\right)\bigg]'=f'(g(x))\cdot g'(x)\\\\\bigg[nf(x)\bigg]'=nf'(x)\\\\(x^n)'=nx^{n-1}

6 0
3 years ago
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