8 xy + 1 =<br><br> PLEASE I CAN’T DO MATH

How is this solved using trig identities (sum/difference)?

GenaCL600 [577]

FIRST PART
We need to find sin α, cos α, and cos β, tan β
α and β is located on third quadrant, sin α, cos α, and sin β, cos β are negative

Determine ratio of ∠α
Use the help of right triangle figure to find the ratio
tan α = 5/12
side in front of the angle/ side adjacent to the angle = 5/12
Draw the figure, see image attached

Using pythagorean theorem, we find the length of the hypotenuse is 13
sin α = side in front of the angle / hypotenuse
sin α = -12/13

cos α = side adjacent to the angle / hypotenuse
cos α = -5/13

Determine ratio of ∠β
sin β = -1/2
sin β = sin 210° (third quadrant)
β = 210°

$cos \beta = -\frac{1}{2} \sqrt{3}$

$tan \beta= \frac{1}{3} \sqrt{3}$

SECOND PART
Solve the questions
Find sin (α + β)
sin (α + β) = sin α cos β + cos α sin β
$sin( \alpha + \beta )=(- \frac{12}{13} )( -\frac{1}{2} \sqrt{3})+( -\frac{5}{13} )( -\frac{1}{2} )$
$sin( \alpha + \beta )=(\frac{12}{26}\sqrt{3})+( \frac{5}{26} )$
$sin( \alpha + \beta )=(\frac{5+12\sqrt{3}}{26})$

Find cos (α - β)
cos (α - β) = cos α cos β + sin α sin β
$cos( \alpha + \beta )=(- \frac{5}{13} )( -\frac{1}{2} \sqrt{3})+( -\frac{12}{13} )( -\frac{1}{2} )$
$cos( \alpha + \beta )=(\frac{5}{26} \sqrt{3})+( \frac{12}{26} )$
$cos( \alpha + \beta )=(\frac{5\sqrt{3}+12}{26} )$

Find tan (α - β)
$tan( \alpha - \beta )= \frac{ tan \alpha-tan \beta }{1+tan \alpha tan \beta }$
$tan( \alpha - \beta )= \frac{ \frac{5}{12} - \frac{1}{2} \sqrt{3} }{1+(\frac{5}{12}) ( \frac{1}{2} \sqrt{3})}$

Simplify the denominator
$tan( \alpha - \beta )= \frac{ \frac{5}{12} - \frac{1}{2} \sqrt{3} }{1+(\frac{5\sqrt{3}}{24})}$
$tan( \alpha - \beta )= \frac{ \frac{5}{12} - \frac{1}{2} \sqrt{3} }{ \frac{24+5\sqrt{3}}{24} }$

Simplify the numerator
$tan( \alpha - \beta )= \frac{ \frac{5}{12} - \frac{6}{12} \sqrt{3} }{ \frac{24+5\sqrt{3}}{24} }$
$tan( \alpha - \beta )= \frac{ \frac{5-6\sqrt{3}}{12} }{ \frac{24+5\sqrt{3}}{24} }$

Simplify the fraction
$tan( \alpha - \beta )= (\frac{5-6\sqrt{3}}{12} })({ \frac{24}{24+5\sqrt{3}})$
$tan( \alpha - \beta )= \frac{10-12\sqrt{3} }{ 24+5\sqrt{3}}$

7 0

3 years ago

There are 99 males and 121 females participating in a marathon. What participants are females?

notsponge [240]

Answer:

121..??

Step-by-step explanation:

4 0

3 years ago

Help please I need it

bonufazy [111]

Answer:

pick B trust me trust me trust me

5 0

3 years ago

Daniel picked out a book to give his dad for his birthday. Daniel only has 63cents from his piggy bank. His mom said she would p

Sauron [17]

Answer:

$13.44

Step-by-step explanation:

Daniel's money + Mom's money = $12.81 + $0.63

That is $13.44.

Hope that helps!

5 0

3 years ago

2x – 1 = y + 4<br>3y +1 = 3х – 2

ehidna [41]

Answer:x=4 y=3

Step-by-step explanation:

Let's solve your system by substitution.

2x−1=y+4;3y+1=3x−2

Step: Solve2x−1=y+4for y:

2x−1=y+4

2x−1+−y=y+4+−y(Add -y to both sides)

2x−y−1=4

2x−y−1+−2x=4+−2x(Add -2x to both sides)

−y−1=−2x+4

−y−1+1=−2x+4+1(Add 1 to both sides)

−y=−2x+5

−y

−1

=

−2x+5

−1

(Divide both sides by -1)

y=2x−5

Step: Substitute2x−5foryin3y+1=3x−2:

3y+1=3x−2

3(2x−5)+1=3x−2

6x−14=3x−2(Simplify both sides of the equation)

6x−14+−3x=3x−2+−3x(Add -3x to both sides)

3x−14=−2

3x−14+14=−2+14(Add 14 to both sides)

3x=12

3x

3

=

12

3

(Divide both sides by 3)

x=4

Step: Substitute4forxiny=2x−5:

y=2x−5

y=(2)(4)−5

y=3(Simplify both sides of the equation)

3 0

3 years ago

8 xy + 1 = PLEASE I CAN’T DO MATH