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IrinaVladis [17]
3 years ago
10

I need help please it need to be correct

Mathematics
1 answer:
Rasek [7]3 years ago
7 0
The answer is 1,816!!!!!
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Which table shows exponential decay?
vazorg [7]
I dknt see anything but just numbers no pic so ima guess 8
5 0
3 years ago
Linear equations 3(x+1)=3x+3
vaieri [72.5K]
4x + 2 - 3x + 5 - 2(x + 5) = (2x - 5) + (3x + 4) 
4x + 2 - 3x + 5  - 2x - 10 =   2x - 5 +   3x + 4 
4x - 3x - 2x + 5 + 2 - 10  =  2x + 3x - 5 + 4 
        - x             - 3           =       5x       - 1   
-x - 3 = 5x - 1 is the line above recopied 
+x     = +x       
    -3   = 6x - 1 
<span>    +1   =    + 1 </span>
    - 2   = 6x 
    - 2/6 = 6x/6 
    - 1/3 = x, the answer
3 0
3 years ago
Identify the unit rate in the graph. A ) 80 Sting B) 60 09 40 D) 20​
AveGali [126]

Answer:

C - 40

Step-by-step explanation:

The unit rate in a graph is how much a unit increases with time. The unit here is Distance (mi) and the time here is Time (h). So to find the unit rate, you divide the y-value with its corresponding x-value (given it is a straight line, which it is in this case).

So for example, let's take the unit 80mi, its corresponding x-value is 2, so 80/2 = 40. Let's do the same for 160mi, its corresponding x-value is 4, so 160/4 = 40 and so on. The value will be the same for all x-y values in the graph.

3 0
3 years ago
Read 2 more answers
Harry is making cookies. He needs 1 3/4 cups of flour for one batch, but he wants to make 1 1/2 batches. Write an equation that
Andrei [34K]

Answer: 1 3/4 × 1 1/2

Step-by-step explanation:

Since Harry needs 1 3/4 cups of flour for one batch of cookies, but he wants to make 1 1/2 batches, the equation that can be used to find how many cups of flour Harry will need will be:

= (1 3/4 / 1) × 1 1/2

= 1 3/4 × 1 1/2

Therefore, to make 1 1/2 batches, the cups of flour needed will be:

= 1 3/4 × 1 1/2

= 7/4 × 3/2

= 21/8

= 2 5/8 cups of flours.

7 0
3 years ago
Which of the following functions f : {0, 1, 2, 3} ! {0, 1, . . . , 7} are one-to-one?
allsm [11]

Answer:

1. No.

f(0)=0\\1^2=1; \text{then } f(1)=1\\2^2=4\equiv 4 \text{ mod 8}; \text{then } f(2)=4\\3^2=9\equiv 1 \text{mod 8 }; \text{then } f(3)=1

Since f(1)=f(3) and 1\neq 3 then f isn't one-to-one.

2. No

f(0)=0\\1^3=1\equiv 1\text{ mod 8}; \text{then } f(1)=1\\2^3=8\equiv 0\text{ mod 8}; \text{then } f(2)=0\\3^3=27\equiv 3 \text{ mod 8}; \text{then } f(3)=3

Since f(0)=f(2) and 0\neq 2 then f isn't one-to-one.

3. No

0^3-8=-8\equiv 0\text{ mod 8}; \text{then } f(0)=0\\1^3-8=-7\equiv 1\text{ mod 8}; \text{then } f(1)=1\\2^3-8=0\equiv 0 \text{ mod 8}; \text{then } f(2)=0\\3^3-8=27-8=19\equiv 3 \text{ mod 8}; \text{then } f(3)=3\\

Since f(0)=f(2) and 0\neq 2 then f isn't one-to-one.

4. Yes

0^3+2*0=0; \text{then } f(0)=0\\1^3+2*1=3\equiv 3\text{ mod 8};  \text{then } f(1)=3\\2^3+2*2=8+4=12\equiv 4 \text{ mod 8};  \text{then } f(2)=4\\3^3+2*3=27+6=33\equiv 1\text{ mod 8};  \text{then } f(3)=1

Since f(0)\neq f(1)\neq f(2) \neq f(3), then f is one-to-one

5. Since f(1)=f(3) and 1\neq 3 then, f isn't one-to-one

3 0
4 years ago
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