Y=(x-3)^2+36
Using (a-b)^2=a^2-2ab+b^2, with a=x and b=3
y=(x)^2-2(x)(3)+(3)^2+36
y=x^2-6x+9+36
y=x^2-6x+45
Answer: Option C. y=x^2-6x+45
Answer:
<u>$4800</u>
Step-by-step explanation:
The expected net income is the probability when rains multiplied by net income (profit) summed with the probability of not raining with that days net income multiplied.
First, Chance of rain = 12% = 12/100 = 0.12
Profit/Loss = Income - Cost
Income is 5000
Cost = 9000
So,
Loss = 5000 - 9000 = 4000
Or, Net Income (profit) = - 4000
Now, Change of not raining = 100 - 12 = 88% = 88/100 = 0.88
Profit = Income - Cost
Income = 15,000
Cost = 9000
Net Income (profit) = 15000 - 9000 = 6000
So, we can write the expected net income as:
<u>Expected NI </u>= (0.12)(-4000) + (0.88)(6000) = <u>$4800</u>
Answer:
Either -4n or 0n but most likely -4n
Answer: I'm not entirely sure, but maybe 1/x^2?
Answer:
A child's toy consists of a piece of plastic attached to a spring in the figure below. The spring is compressed against the floor a distance of 2.00 cm, and the toy is released. If the toy has a mass of 117 g and rises to a maximum height of 45.0 cm, estimate the force constant of the spring.
Step-by-step explanation:
