Answer:
Width: x + 3
(Length, width):
(5,4) (6,5) (7,6)
Step-by-step explanation:
x² + 7x + 12
x² + 4x + 3x + 12
x(x + 4) + 3(x + 4)
(x + 4)(x + 3)
Longer one is the length,
With is (x + 3)
x = 1,
5 × 4
x = 2,
6 × 5
x = 3,
7 × 6
<span>10q + 5 = 5q + 5q + 5
so
answer is
</span><span>
A. 5q+5q+5</span>
Call (F) the age of the father and (J) the age of Julio
The F & J are related in this way: F=4J
Now you have a restriction in the form of inequality: The sum of both ages has to be greater or equal than 55.
Algebraically that is: F + J ≥ 55
You can substitute F with 4J to find the solution for J:
4J + J ≥ 55
5J ≥ 55
Now divide both sides by 5
5J/5 ≥ 55/5
J ≥ 11
That Imposes a lower boundary for the value of J of 11, meaning that the youngest age of Julio can be 11
Answer:x=-20
Step-by-step explanation:
