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2 years ago

I have a triangle: Angle A = 3x +28; Angle B = 5x +52; Angle C = 2x - 10: Solve for X

Mathematics

2 answers:

Jet001 [13]2 years ago

6 0

I have no clue if I even did this right but here’s my work. I don’t wanna get it wrong for you!

Alex17521 [72]2 years ago

6 0

Answer: x=11

Explanation: The anglers in a triangle must all add to 180.

Therefore, we can use the equation 180=3x+28+5x+52+2x-10

Combing like terms gives us 180=10x+70

Solving for x gives us 11.

To check our work, we can plug in 11 for x.

3(11)+28+5(11)+52+2(11)-10=180.

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What is number of terms for 32y- 28

Sholpan [36]

Answer:

2 terms

Step-by-step explanation:

hope this helps! :D

have a miraculous day!! <3

7 0

2 years ago

At Niagra High, Mr. Borton bought 4 student tickets and 2 adult tickets for the high school musical which cost $64. then Mrs. Ge

balandron [24]

Answer:

Each student ticket costs $8.33

Each adult ticket costs $15.34

Step-by-step explanation:

At Niagra High, Mr. Borton bought 4 student tickets and 2 adult tickets for the high school musical which cost $64. then Mrs. Gelvoria bought 3 student tickets and 3 adult tickets for the show and it cost her $72. How much are each type of tickets?

s = cost of each student ticket

a = cost of adult ticket

Our system of equations:

4s + 2a = 64

3s + 3a = 71

-3(4s + 2a = 64) ==> -12s - 6a = -192

2(3s + 3a = 71) ==> 6s + 6a = 142

-12s - 6a = -192

6s + 6a = 142

-6s = -50

/-6 /-6

s = $8.33 (the cost of each student ticket)

Now, let's find the cost of each adult ticket:

4s + 2a = 64

4(8.33) + 2a = 64

33.32 + 2a = 64

-33.32 -33.32

2a = 30.68

/2 /2

a = 15.34 (the cost of each adult ticket)

(x, y) ==> (8.33, 15.34)

Check your answer:

4s + 2a = 64

4(8.33) + 2(15.34) = 64

33.32 + 30.68 = 64

64 = 64

This statement is true

Hope this helps!

8 0

2 years ago

Just number 23 super confused

vodka [1.7K]

Answer:

x = -7

Step-by-step explanation:

This is an exponential equation.

$\frac{1}{2}^x=128$

We need to take log(or ln) of both sides and use logarithm property to solve this.

So, let's take ln of both sides, so we have:

$ln(\frac{1}{2}^x)=ln(128)$

Now, we will use this property shown below to further simplify:

$ln(a^b)=bln(a)$

So, we now have:

$ln(\frac{1}{2}^x)=ln(128)\\xln(\frac{1}{2})=ln(128)\\x=\frac{ln(128)}{ln(\frac{1}{2})}\\x=-7$

The value of x is -7

6 0

3 years ago

Secant RM intersects secant RN at point R. Find the length of RQ. If necessary, round to the hundredths place.

QveST [7]

Answer:

3 Units

Step-by-step explanation:

Secant RM intersects secant RN at point R.

The secants intersects the circle at points P and Q respectively as seen in the diagram.

To determine the length of RQ, we use the Theorem of Intersecting Secants.

Applying this on the diagram, we have:

RP x RN=RQ X RM

4(4+5)=RQ(RQ+9)

Let the length of RQ=x

$4*9=x^2+9x\\36=x^2+9x\\x^2+9x-36=0\\x^2+12x-3x-36=0\\x(x+12)-3(x+12)=0\\(x+12)(x-3)=0\\x+12=0$ x-3=0\\x=-12 or x=3\\Since x cannot be negative$\\x=|RQ|=3$