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3 years ago

11

A gene carries the______ for a trait.

1 answer:

MrRissso [65]3 years ago

8 0

Answer:

A gene carries the <u>information</u> for a trait.

Step-by-step explanation:

Just got it right on edge

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What equation do you get when you solve z - m = z + bx for x

olganol [36]

You get: x=-m/b ( z cancels out)

4 0

3 years ago

SAT math scores have a bell-shaped distribution with a mean of 515 and a standard deviation of 114.

nadezda [96]

Hey there mate :)

Analysis :

$401 = 515 - 114 = u - 6$

And

$173 = 515 - 3.114 = u - 36$

$= \frac{p(u - 36 < u < u + 36) - p(u - 6 < u < u + 6)}{2}$

$= \frac{99.73percent - 68.21percent}{2}$

$= \frac{31.46percent}{2}$

$= {15.73percent}$

Then, calculating,

$u - 26 = 515 - 2 \times 114 = 287$

And

$u + 26 = 515 + 2 \times 114 = 743$

Then,

$The \: Range = (287,743)$

Final Answers :-

<u>1</u><u>5</u><u>.</u><u>7</u><u>3</u><u> </u><u>%</u>

<u>(</u><u>2</u><u>8</u><u>7</u><u>,</u><u>7</u><u>4</u><u>3</u><u>)</u>

~Benjemin360

3 0

2 years ago

Convert from rectangular to polar coordinates: note: choose rr and θθ such that rr is nonnegative and 0≤θ<2π0≤θ<2π (a)(9,0

DochEvi [55]

Answer:

Step-by-step explanation:

Convert rectangle (x , y) to polar coordinates ( r , θ)

$x=r \cos \theta, y= r \sin \theta$

$r=\sqrt{x^2+y^2} , \theta =tan^-^1 (\frac{y}{x} )$

a) converts (9, 0) to polar coordinates ( r , θ)

$r=\sqrt{x^2+y^2} \\\\=\sqrt{9^2+0} \\\\=9$

$\theta= \tan^-^1 (\frac{0}{9} )\\\\=0$

b) Convert $(18,\frac{18}{\sqrt{3} } )$ to polar coordinates ( r, θ)

$r = \sqrt{18^2+(\frac{18}{\sqrt{3} })^2 } \\\\=\sqrt{324+108} \\\\=\sqrt{432}$

$\frac{x}{y} \theta = \tan^-^1(\frac{\frac{18}{\sqrt{3} } }{18} )\\\\= \tan ^-^1(\frac{1}{\sqrt{3} } )\\\\= \frac{\pi}{6}$

c) converts (-5, 5) to polar coordinates ( r , θ)

$r =\sqrt{(-5)^2+(5)^2} \\\\=\sqrt{50} \\\\=5\sqrt{2}$

$\theta=\tan^-^1(\frac{5}{-5} )\\\\= \tan^-^1(-1)\\\\=\frac{3\pi}{4}$

d) converts (-1, √3) to polar coordinates ( r , θ)

$r=\sqrt{(-1)^2+(\sqrt{3})^2 } \\\\= \sqrt{4} \\\\=2$

$\theta=\tan^-^1(\frac{\sqrt{3} }{-1} )\\\=\tan^-^1(-\sqrt{3} )\\\\=\frac{2\pi}{3}$

$= \frac{2\pi}{\sqrt{3} }$

6 0

3 years ago

fgiga [73]

B) f(x) = 3

It’s because all the y values are 3

5 0

2 years ago

PLEASE HELP! WILL GIVE BRAINLIEST!

atroni [7]

4 its 4444444444444444

8 0

3 years ago

Read 2 more answers