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Elena L [17]
3 years ago
5

The diameter of a sphere is 4 centimeters. Which represents the volume of the sphere?

Mathematics
1 answer:
soldier1979 [14.2K]3 years ago
3 0

Answer:

32\pi/3 cm³

Step-by-step explanation:

If the diameter is 4 cm, then the radius is 2 cm.

Use the sphere volume formula:

V = 4/3\pir³

Plug in the radius and solve:

V = 4/3\pi(2)³

V = 4/3\pi(8)

V = 32\pi/3

So, the volume of the sphere is 32\pi/3 cm³

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. A patio is built in the shape of a trapezoid, as shown. Determine the area of the patio.
netineya [11]

Answer:

84 in²

Step-by-step explanation:

(15+6)0.5 * 8 = 21(0.5) * 8 = 10.5 * 8 = 84

8 0
3 years ago
XY is a diameter of a circle and Z is a point on the circle such that ZY=6. If the area of the triangle XYZ is 18 square root 3
nataly862011 [7]
<h2>Answer:</h2>

4π

<h2>Step-by-step explanation:</h2>

As shown in the diagram, triangle XYZ is a right triangle. Therefore, its area (A) is given by:

A = \frac{1}{2} x b x h      -------------(i)

Where;

A = 18\sqrt{3}

b = XZ = base of the triangle

h = YZ = height of the triangle = 6

<em>Substitute these values into equation(i) and solve as follows:</em>

18\sqrt{3} =  \frac{1}{2} x b x 6

18\sqrt{3} =  3b

<em>Divide through by 3</em>

6\sqrt{3} =  b

Therefore, b = XZ = 6\sqrt{3}

<em>Now, assume that the circle is centered at O;</em>

Triangle XOZ is isosceles, therefore the following are true;

(i) |OZ| = |OX|

(ii) XZO = ZXO = 30°

(iii) XOZ + XZO + ZXO = 180°   [sum of angles in a triangle]

=>  XOZ + 30° + 30° = 180°

=>  XOZ + 60° = 180°

=>  XOZ = 180° - 60°

=>  XOZ = 120°

Therefore we can calculate the radius |OZ| of the circle using sine rule as follows;

\frac{sin|XOZ|}{XZ} = \frac{sin|ZXO|}{OZ}

\frac{sin120}{6\sqrt{3} } = \frac{sin 30}{OZ}

\frac{\sqrt{3} /2}{6\sqrt{3} } = \frac{1/2}{|OZ|}

\frac{1}{12}  = \frac{1}{2|OZ|}

\frac{1}{6} = \frac{1}{|OZ|}

|OZ| = 6

The radius of the circle is therefore 6.

<em>Now, let's calculate the length of the arc XZ</em>

The length(L) of an arc is given by;

L = θ / 360 x 2 π r          ------------------(ii)

Where;

θ = angle subtended by the arc at the center.

r = radius of the circle.

In our case,

θ = ZOX = 120°

r = |OZ| = 6

Substitute these values into equation (ii) as follows;

L = 120/360 x 2π x 6

L = 4π

Therefore the length of the arc XZ is 4π

5 0
3 years ago
What is a possible value of sin(theta) when cos2(theta)=0.73?
Sindrei [870]
We use the following trigonometric identity to answer the question:
 sin^ 2 (theta) + cos^ 2 (theta) = 1
 We substitute the values:
 sin ^ 2 (theta) + 0.73 = 1
 We cleared:
 sin ^ 2 (theta) = 1-0.73
 sin ^ 2 (theta) = 0.27
 Answer:
 a possible value of sin ^ 2 (theta) is:
 
c.0.26 (nearest option)
8 0
3 years ago
2
Rainbow [258]

Answer:

tha anser us B

Step-by-step explanation:

it is very easy you just read the question carefully

6 0
3 years ago
How to classify this conic ecwation 4x^2+9y^2-54y-63=0
MArishka [77]
This looks like an ellipse.
Complete the square for y: 9(y²-6y-7)=9(y²-6y+9-9-7)=9((y-3)²-16).
Rewrite the equation:
4x²+9(y-3)²-144=0; 4x²/144+9(y-3)²/144=1; x²/36+(y-3)²/16=1.
Standard equation of an ellipse is (x-h)²/a²+(y-k)²/b²=1, where (h,k) is the origin or centre.
This is the equation of an ellipse with centre (0,3), a=6 and b=4 (semimajor and semiminor axes).
6 0
3 years ago
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