All categories

1 year ago

100 POINTS

Mathematics

2 answers:

JulijaS [17]1 year ago

4 0

Answer:

Small one is 4ft larger one is 12ft

zvonat [6]1 year ago

4 0

Answer:

Small cube: 4 feet

Large cube: 12 feet

Step-by-step explanation:

So, for the small cube, we know that side x side x side will equal 64, the volume.

4 x 4 x 4 = 64, so 4 is the side length for the small cube.

For the large cube, it is just the small side multiplied by 3.

So, 4 x 3 = 12, the length of the larger cube's side.

You might be interested in

4a^2 - 7b + 2ab - a^2 + b

Andrej [43]

Answer:

3a^2 - 6b + 2ab

Step-by-step explanation:

Put all the like terms together

(4a^2 - a^2) - (7b + b) + 2ab

then simplify

(4a^2 - a^2) = 3a^2

(-7b + b) = -6b

then rewrite

3a^2 - 6b + 2ab

3 0

3 years ago

Read 2 more answers

A mirror should be centered on a wall. The mirror is 4 feet wide and the wall is 20 feet wide. Which equation helps determine th

Alinara [238K]

A.) x+4+x=20 should be the answer

7 0

2 years ago

Find the indefinite integral using the substitution x = 10 sin(θ). (Use C for the constant of integration.) 1 (100 − x2)3/2 dx

soldi70 [24.7K]

Answer:

The indefinite integral

= $\frac{1}{100}$ ˣ $\frac{x}{\sqrt{100-x^{2} } }$ ⁺ C

Step-by-step explanation:

x= 10sinθ

dx = 10cosθdθ

the step-to-step explanation is in the attachment

3 0

2 years ago

I need to know give 20 points to who answers this right.

NISA [10]

Step-by-step explanation:

I believe it's 16 1/2. I just used MathPapa lol.

5 0

2 years ago

What is the solution of x=2+ square root x-2?

alex41 [277]

So I'm going to assume that this question is asking for non extraneous solutions, or solutions that are found in the equation and are valid solutions when plugged back into the equation. So firstly, subtract 2 on both sides of the equation:

$x-2=\sqrt{x-2}$

Next, square both sides:

$(x-2)^2=x-2\\(x-2)(x-2)=x-2\\x^2-4x+4=x-2$

Next, subtract x and add 2 to both sides of the equation:

$x^2-5x+6=0$

Now we are going to be factoring by grouping to find the solution(s). Firstly, what two terms have a product of 6x^2 and a sum of -5x? That would be -3x and -2x. Replace -5x with -2x - 3x:

$x^2-2x-3x+6=0$

Next, factor x^2 - 2x and -3x + 6 separately. Make sure that they have the same quantity on the inside of the parentheses:

$x(x-2)-3(x-2)=0$

Now you can rewrite the equation as $(x-3)(x-2)=0$

Now, apply the Zero Product Property and solve for x as such:

$x-3=0\\x=3\\\\x-2=0\\x=2$

Now, it may appear that the answer is C, however we need to plug the numbers back into the original equation to see if they are true as such:

$2=2+\sqrt{2-2}\\2=2+\sqrt{0}\\2=2+0\\2=2\ \textsf{true}\\\\3=2+\sqrt{3-2}\\3=2+\sqrt{1}\\3=2+1\\3=3\ \textsf{true}$

Since both solutions hold true when x = 2 and x = 3, your answer is C. x = 2 or x = 3.

8 0

2 years ago