Answer:
6 four-packs.
Step-by-step explanation:
My reasoning for 6 four-packs is that, the shopper needs 24, right? And if that shopper buys 6 four-packs it'll be cheaper than the larger package. The 6 four-packs come to a cost of $20.04. But the 4 six-packs will come out as $21.12. The shopper will be able to save $1.08 :)
For the set B= { 3, 5, 7, ,9 , 12, 17, } determine n(B)
n is asking for the count of numbers in the set.
Set B has 6 numbers.
n(B) = 6
Answer:
99.73% of bags contain between 62 and 86 chips .
Step-by-step explanation:
We are given that the number of chips in a bag is normally distributed with a mean of 74 and a standard deviation of 4.
Let X = percent of bags containing chips
So, X ~ N()
The standard normal z score distribution is given by;
Z = ~ N(0,1)
So, percent of bags contain between 62 and 86 chips is given by;
P(62 < X < 86) = P(X < 86) - P(X <= 62)
P(X < 86) = P( < ) = P(Z < 3) = 0.99865 {using z table}
P(X <= 62) = P( <= ) = P(Z <= -3) = 1 - P(Z < 3)= 1 - 0.99865 = 0.00135
So, P(62 < X < 86) = 0.99865 - 0.00135 = 0.9973 or 99.73%
Therefore, 99.73% of bags contain between 62 and 86 chips .