A 21-inch rope is to be cut into two pleces so that one piece is 8 inches longer than twice the other. How long is each piece, i
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Answer:
Part A
The bearing of the point 'R' from 'S' is 225°
Part B
The bearing from R to Q is approximately 293.2°
Step-by-step explanation:
The location of the point 'Q' = 35 km due East of P
The location of the point 'S' = 15 km due West of P
The location of the 'R' = 15 km due south of 'P'
Part A
To work out the distance from 'R' to 'S', we note that the points 'R', 'S', and 'P' form a right triangle, therefore, given that the legs RP and SP are at right angles (point 'S' is due west and point 'R' is due south), we have that the side RS is the hypotenuse side and ∠RPS = 90° and given that =
, the right triangle ΔRPS is an isosceles right triangle
∴ ∠PRS = ∠PSR = 45°
The bearing of the point 'R' from 'S' measured from the north of 'R' = 180° + 45° = 225°
Part B
∠PRQ = arctan(35/15) ≈ 66.8°
Therefore the bearing from R to Q = 270 + 90 - 66.8 ≈ 293.2°
For this case we must solve the following questions:
Question 1:
We should simplify the following expression:
Applying double C we have:
By definition of multiplication of powers of the same base we have to place the same base and add the exponents:
Canceling common terms:
Answer:
Option A
Question 2:
We should simplify the following expression:
So, we have:
Simplifying common terms:
Answer:
Option D
Question 3:
We factor the following expressions to rewrite the experience:
<em>: </em>We look for two numbers that multiplied give 10 and added 7:
<em></em> We look for two numbers that multiplied give -50 and added -5:
<em></em>
Rewriting the given expression we have:
We simplify common terms in the numerator and denominator we have:
Answer:
Option D
Answer:
Option D will be your answer
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