The answer is = 4 x 2 − 20 x + 26 Explanation: This is a composition of functions f ( x ) = 2 x − 5 g ( x ) = x 2 + 1 g ( f ( x ) ) = g ( 2 x − 5 ) = ( 2 x − 5 ) 2 + 1 = 4 x 2 − 20 x + 25 + 1 = 4 x 2 − 20 x + 26 f ( g ( x ) ) = f ( x 2 + 1 ) = 2 ( x 2 + 1 ) − 5 = 2 x 2 + 2 − 5 = 2 x 2 − 3 g ( f ( x ) ) ≠ f ( g ( x ) )