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Anni [7]
3 years ago
9

Find angle abc (2x+14) (x+7)

Mathematics
2 answers:
melisa1 [442]3 years ago
7 0
It's a complementary angle, so just solve for x and subtract the CBD from 90, 
First, we have to solve for x.
2x + 14 + x + 7 = 90
Combine like terms
3x + 21 = 90
Balance, subtract 21 from each side.
3x = 69
Divide 3 from each side
x = 23.
So know that we know x is 23, we can go about it 2 ways, subtracting the other angle with 90 or just substituting the variable, I'd just substitute the variable for it so just do 23 + 7. That equals 30, angle ABC = 30.


Nata [24]3 years ago
6 0
Angles represented by 2x+14 and x+7 must add up to 90 degrees.  Thus,

2x+14 + x+7 = 90, so that

3x + 21 = 90, or 3x = 69, or x = 23.

Then angle ABC is x+7, or 23+7, or 30 degrees.

If that's the case, then angle CBD must be 60 degrees.  Is it?
Subst. 23 for x in 2x+14:  2(23)+14 =46+14 = 60 (degrees).  YES.


You might be interested in
5n+9=2n solve equation
julsineya [31]

5n+9=2n

5n+9−2n=2n−2n

3n+9=0

3n+9−9=0−9

3n=−9

3n/3=−9/3

n=−3

4 0
3 years ago
Would i solve this doing 14+5 or 14-5 to get the missing length?
nataly862011 [7]

Answer:

The answer to your question is 10 ft

Step-by-step explanation:

We can observe that all the sides have a length but the first to the left.

Also, we know the corners meet at right triangles, so to calculate the length of the missing side, we must add to sides.

But these sides must be the ones that are in front of it (6 ft and 4 ft)

Then    ? = 6 + 4

               10 ft

3 0
3 years ago
From a survey of 60 students attending a university, it was found that 9 were living off campus, 36 were undergraduates, and 3 w
lana66690 [7]
I think the question has to do with the number of students who are attending the university but is neither an undergraduate nor living off-campus. To help us solve this problem, we use the Venn diagram as shown in the picture. The intersection of the 2 circles would be 3 students. The students in the 'students living off-campus' circle would be 9 - 2 = 6, while the undergraduate students would be 36-3 = 33. The total number of students inside all the circles and outside the circles should sum up to 60 students.

6 + 3 + 33 + x = 60
x = 60 - 6 - 3 - 3
x = 18 students

Therefore, there are 18 students who are neither an undergraduate nor living off-campus

8 0
3 years ago
Out of 100 employees at a company, 92 employees either work part time or work 5 days each week. There are 14 employees who work
Alexus [3.1K]

Answer: 0.02

Step-by-step explanation:

OpenStudy (judygreeneyes):

Hi - If you are working on this kind of problem, you probably know the formula for the probability of a union of two events. Let's call working part time Event A, and let's call working 5 days a week Event B. Let's look at the information we are given. We are told that 14 people work part time, so that is P(A) = 14/100 - 0.14 . We are told that 80 employees work 5 days a week, so P(B) = 80/100 = .80 . We are given the union (there are 92 employees who work either one or the other), which is the union, P(A U B) = 92/100 = .92 .. The question is asking for the probability of someone working both part time and fll time, which is the intersection of events A and B, or P(A and B). If you recall the formula for the probability of the union, it is

P(A U B) = P(A) +P(B) - P(A and B).

The problem has given us each of these pieces except the intersection, so we can solve for it,

If you plug in P(A U B) = 0.92 and P(A) = 0.14, and P(B) = 0.80, you can solve for P(A and B), which will give you the answer.

I hope this helps you.

Credit: https://questioncove.com/updates/5734d282e4b06d54e1496ac8

7 0
2 years ago
HELP ME IT'S URGENT I COULD FAIL
hjlf

Answer:

pm+2=8

Step-by-step explanation:

Given,

m=3

p=3

We know,

pm+2=3(3)+2

=3×3+2

=6+2

=8

5 0
2 years ago
Read 2 more answers
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