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Elanso [62]
3 years ago
14

Provided the amplitude is sufficiently great, the human ear can respond to longitudinal waves over a range of frequencies from a

bout 20.0 Hz to about 20.0 kHz.a)If you were to mark the beginning of each complete wave pattern with a red dot for the long-wavelength sound, how far apart would the red dots be?b)If you were to mark the beginning of each complete wave pattern with a blue dot for the short-wavelength sound, how far apart would the blue dots be?c)In reality would adjacent red dots be far enough apart for you to easily measure their separation with a meterstick?d)In reality would adjacent blue dots be far enough apart for you to easily measure their separation with a meterstick?e)Suppose you repeated part A in water, where sound travels at 1480 {\rm{ m/s}}. How far apart would the red dots be ?f)Suppose you repeated part A in water, where sound travels at 1480 {\rm{ m/s}}. How far apart would the blue dots be ?g)Could you readily measure their separation with a meterstick?
Physics
1 answer:
riadik2000 [5.3K]3 years ago
8 0

Answer:

Check the explanation

Explanation:

The beat frequency is

df = f2 - f1

the wavelength is

lamda1 = (v/f1)

and lamda2 = (v/f2)

where v = 340 m/s,f1 = 25.0 kHz and f2 = 20.0 kHz

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The angle between incident ray and reflected ray is 80 degrees. What is the value of angle of incidence?
saul85 [17]

Answer:

The angle of incident ray is 40°.

Explanation:

Given that the angle of incident and reflected ray are the same. In this question, we had given that both angles added up will gives you 80° so you have to divide it by 2 :

incident + reflected = 80°

Let incident = reflected = θ

θ + θ = 80°

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3 years ago
100 POINTS AND BRAINLIEST.
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Answer:

I think the answer must be A.

5 0
2 years ago
Determine the capacitive reactance for a 20 uF capacitor that is across a 20 volt, 60 Hz source
aleksandr82 [10.1K]

Answer:

Capacitive reactance is 132.6 Ω.

Explanation:

It is given that,

Capacitance, C=20\ \mu F=20\times 10^{-6}\ F=2\times 10^{-5}\ F

Voltage source, V = 20 volt

Frequency of source, f = 60 Hz

We need to find the capacitive reactance. It is defined as the reactance for a capacitor. It is given by :

X_C=\dfrac{1}{2\pi fC}

X_C=\dfrac{1}{2\pi \times 60\ Hz\times 2\times 10^{-5}\ F}

X_C=132.6\ \Omega

So, the capacitive reactance of the capacitor is 132.6 Ω. Hence, this is the required solution.

4 0
3 years ago
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