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Elanso [62]
3 years ago
14

Provided the amplitude is sufficiently great, the human ear can respond to longitudinal waves over a range of frequencies from a

bout 20.0 Hz to about 20.0 kHz.a)If you were to mark the beginning of each complete wave pattern with a red dot for the long-wavelength sound, how far apart would the red dots be?b)If you were to mark the beginning of each complete wave pattern with a blue dot for the short-wavelength sound, how far apart would the blue dots be?c)In reality would adjacent red dots be far enough apart for you to easily measure their separation with a meterstick?d)In reality would adjacent blue dots be far enough apart for you to easily measure their separation with a meterstick?e)Suppose you repeated part A in water, where sound travels at 1480 {\rm{ m/s}}. How far apart would the red dots be ?f)Suppose you repeated part A in water, where sound travels at 1480 {\rm{ m/s}}. How far apart would the blue dots be ?g)Could you readily measure their separation with a meterstick?
Physics
1 answer:
riadik2000 [5.3K]3 years ago
8 0

Answer:

Check the explanation

Explanation:

The beat frequency is

df = f2 - f1

the wavelength is

lamda1 = (v/f1)

and lamda2 = (v/f2)

where v = 340 m/s,f1 = 25.0 kHz and f2 = 20.0 kHz

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B.False

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Suppose a particle moves along a straight line with velocity v(t)=t2e−2tv(t)=t2e−2t meters per second after t seconds. How many
dimulka [17.4K]

Explanation:

It is given that,

Velocity of the particle moving in straight line is :

v(t)=t^2e^{-2t}\ m/s

We need to find the distance (x)  traveled by the particle during the first t seconds. It is given by :

x=\int\limits {v.dt}

x=\int\limits {t^2e^{-2t}dt}

Using by parts integration, we get the value of x as :

x=\dfrac{-(2t^2+2t+1)e^{-2t}}{4}\ meters

Hence, this is the required solution.

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3 years ago
Mr. Jones's prescription calls for 1.04 tablets per day. Based on this information, how many tablets should Mr. Jones take per d
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Answer:

C.) 1

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3 years ago
A person in bare feet is standing under a tree during a thunderstorm, seeking shelter from the rain. A lightning strike hits the
Anni [7]

Answer:

I=38.181\ A is the current through the body of the man.

E=34.5\ J energy dissipated.

Explanation:

Given:

  • time for which the current lasted, t=43\times 10^{-6}\ s
  • potential difference between the feet, V=21000\ V
  • resistance between the feet, R=550\ \Omega

<u>Now, from the Ohm's law we have:</u>

I=\frac{V}{R}

I=\frac{21000}{550}

I=38.181\ A is the current through the body of the man.

<u>Energy dissipated in the body:</u>

E=I^2.R.t

E=38.181^2\times 550\times 43\times 10^{-6}

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3 years ago
Two blocks are placed at the ends of a horizontal massless board, as in the drawing. The board is kept from rotating and rests o
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Answer:

The magnitude of the angular acceleration ∝ = \frac{rxF}{2.8[tex]r^{2}}[/tex]

Explanation:

The angular acceleration ∝ is equal to the torque (radius multiplied by force) divided by the mass times the square of the radius. The magnitude of angular acceleration ∝ will have the equation above but we have to replace the mass in the equation by 2.8kg as stated.

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3 years ago
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