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Elanso [62]
3 years ago
14

Provided the amplitude is sufficiently great, the human ear can respond to longitudinal waves over a range of frequencies from a

bout 20.0 Hz to about 20.0 kHz.a)If you were to mark the beginning of each complete wave pattern with a red dot for the long-wavelength sound, how far apart would the red dots be?b)If you were to mark the beginning of each complete wave pattern with a blue dot for the short-wavelength sound, how far apart would the blue dots be?c)In reality would adjacent red dots be far enough apart for you to easily measure their separation with a meterstick?d)In reality would adjacent blue dots be far enough apart for you to easily measure their separation with a meterstick?e)Suppose you repeated part A in water, where sound travels at 1480 {\rm{ m/s}}. How far apart would the red dots be ?f)Suppose you repeated part A in water, where sound travels at 1480 {\rm{ m/s}}. How far apart would the blue dots be ?g)Could you readily measure their separation with a meterstick?
Physics
1 answer:
riadik2000 [5.3K]3 years ago
8 0

Answer:

Check the explanation

Explanation:

The beat frequency is

df = f2 - f1

the wavelength is

lamda1 = (v/f1)

and lamda2 = (v/f2)

where v = 340 m/s,f1 = 25.0 kHz and f2 = 20.0 kHz

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A wedge with an inclination of angle θ rests next to a wall. A block of mass m is sliding down the plane. There is no friction b
Softa [21]

Answer:

  The net force on the block  F(net)  = mgsinθ).

   Fw =mg(cosθ)(sinθ)

Explanation:

(a)

Here, m is the mass of the block, n is the normal force, \thetaθ is the wedge angle, and Fw  is the force exerted by the wall on the wedge.

Since the block sliding down, the net force on the block is along the plane of the wedge that is equal to horizontal component of weight of the block.

                    F(net)  = mgsinθ

The net force on the block  F(net)  = mgsinθ).

The direction of motion of the block is along the direction of net force acting on the block. Since there is no frictional force between the wedge and block, the only force acting on the block along the direction of motion is mgsinθ.

(b)

From the free body diagram, the normal force n is equal to mgcosθ .

                           n=mgcosθ

The horizontal component of normal force on the block is equal to force

                           Fw=n*sin(θ) that exerted by the wall on the wedge.

Substitute mgcosθ for n in the above equation;

                           Fw =mg(cosθ)(sinθ)

Since, there is no friction between the wedge and the wall, there is component force acting on the wall to restrict the motion of the wedge on the surface and that force is arises from the horizontal component for normal force on the block.

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A block with mass 0.470 kg sits at rest on a light but not long vertical spring that has spring constant 85.0 N/m and one end on
a_sh-v [17]

Answer: elastic potential energy = 20.27 J

Explanation:

Given that the

Mass M = 0.470 kg

Height h = 4.40 m

Spring constant K = 85 N/m

The maximum elastic potential will be equal to the maximum kinetic energy experienced by the block.

But according to conservative of energy, the maximum kinetic energy is equal to the maximum potential energy experienced by the block of mass M.

That is

K .E = P.E = mgh

Where g = 9.8m/s^2

Substitutes all the parameters into the formula

K.E = 0.470 × 9.8 × 4.4

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