Answer:
E = 4000 N/C
Explanation:
Given the following data;
Force = 0.080 N.
Charge, q = 20 microcoulomb = 20 * 10^-6 = 2 * 10^-5 Coulombs
To find the electric field strength;
Mathematically, the electric field strength is given by the formula;
Electric field strength = force/charge
Substituting into the formula, we have;
E = 0.080/0.00002
E = 4000 N/C
Answer: 1,500m/s
Explanation:
Relationship existing between velocity of a wave (v), wavelength(¶) and frequency(f) is
v = f¶... (1)
Since Frequency (f) is the reciprocal of the period (T);
Frequency = 1/Period i.e F = 1/T... (2)
Substituting equation 2 into 1 we have;
v = 1/T × ¶
v = ¶/T
Given wavelength ¶ = 9m
Period T = 0.006s
v = 9/0.006
v = 1,500m/s
The velocity of the wave will be 1,500m/s
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