Answer:
The arrow-apple combo will move with a velocity 3.6 m/s to the right.
Explanation:
Use the law of conservation of momentum to solve this problem. In this case the law can be written as follows:
from which the desired velocity can be isolated:
The arrow-apple combo will move with a velocity 3.6 m/s to the right.
C. Solution
<span>
More specifically in the macromolecules of the cells.
These macromolecules could either be amino acids, proteins or nucleic acids. They
are responsible for the chemical changes and reactions that affects largely the
cell and its composition. Take for instance the cytoplasm of the cell where
these organelles are settled. These simple organelles are composed of
macromolecules which ignites and catalyses different functions that enables
cells, in macro-perspective in motion and metabolism. In intestines for
example, metabolism happens and breaking down parts of a food to simpler
compounds that are used and these nutrients delivered throughout the body and
again broken down by into smaller components.</span>
Answer:
the first popsicle was made because a kid accidentally left his fruit punch out in his front yard during winter
Explanation:
The energy stored in the capacitor at given capacitance and voltage is determined as 396.5 J.
<h3>Energy stored in the capacitor</h3>
The energy stored in the capacitor is calculated as follows;
E = ¹/₂CV²
where;
V is the voltage
E = ¹/₂ x 13 x 10⁻⁶ x (7.81 x 10³)²
- C is the capacitance
- V is the voltage
E = ¹/₂ x 13 x 10⁻⁶ x (7.81 x 10³)²
E = 396.5 J
Thus, the energy stored in the capacitor at given capacitance and voltage is determined as 396.5 J.
The complete question is below
An electronic defibrillator used on heart attack victims works by delivering charge stored in a capacitor. If the device utilizes a 13.0 μF capacitor charged to 7.81 × 103 V, what is the energy stored in the capacitor?
Learn more about capacitor here: brainly.com/question/13578522
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Answer:
a) t = 2.0 s, b) x_f = - 24.56 m, Δx = 16.56 m
Explanation:
This is an exercise in kinematics, the relationship of position and time is indicated
x = 5 t³ - 9t² -24 t - 8
a) ask when the velocity is zero
speed is defined by
v =
let's perform the derivative
v = 15 t² - 18t - 24
0 = 15 t² - 18t - 24
let's solve the quadratic equation
t =
t1 = -0.8 s
t2 = 2.0 s
the time has to be positive therefore the correct answer is t = 2.0 s
b) the position and distance traveled for a = 0
acceleration is defined by
a = dv / dt
a = 30 t - 18
a = 0
30 t = 18
t = 18/30
t = 0.6 s
we substitute this time in the expression of the position
x = 5 0.6³ - 9 0.6² - 24 0.6 - 8
x = 1.08 - 3.24 - 14.4 - 8
x = -24.56 m
we see that all the movement is in one dimension so the distance traveled is the change in position between t = 0 and t = 0.6 s
the position for t = 0
x₀ = -8 m
the position for t = 0.6 s
x_f = - 24.56 m
the distance
ΔX = x_f - x₀
Δx = | -24.56 -(-8) |
Δx = 16.56 m