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Wittaler [7]
3 years ago
10

A crazy dog runs at a constant speed of 19.85 mi/hr for 6.09 min. How far does the dog travel during this time period?

Physics
1 answer:
Phantasy [73]3 years ago
8 0

Answer:

Distance, d = 3242.19 meters

Explanation:

It is given that,

Speed of the dog, v = 19.85 mi/hr

Since, 1 mph = 0.44704 m/s

v = 19.85 mi/hr = 8.873 m/s

Time taken by the dog, t = 6.09 min = 365.4 sec

Let the distance covered by the dog during this time period is d. It can be calculated by the speed of the dog multiplied by the time taken as :

d=v\times t

d=8.873\times 365.4

d = 3242.19 meters

So, the the dog travel during this time period is 3242.19 meters. Hence, this is the required solution.

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The λmax of 2,3,4-trimethylhexatriene is 280 nm.

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Woodward's rules, sometimes known as Woodward-Fieser rules (after Louis Fieser) and named after Robert Burns Woodward, are a number of sets of empirically developed principles that aim to forecast the wavelength of the absorption maximum (max) in an ultraviolet-visible spectrum of a certain molecule.

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The λmax of 2,3,4-trimethylhexatriene is 280 nm.

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brainly.com/question/16982345

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