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bulgar [2K]
3 years ago
8

I just need examples of these things, I have to make my own problems and solve them:

Mathematics
1 answer:
poizon [28]3 years ago
6 0
1) x+17=20
x-10=30

2) x/4=20
x/30=2

3) 4(x+5)=40

4) x+3.2=6

5) A pizza place sells pizza for $5 per box. If I had $20 how many pizzas can I buy in all? (5x=20)

Hope this helps! Have a wonderful day.
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josiah is ready to purchase a new watch. it is regularly priced at $480.77. the sale price is $380.54. what is the mark down on
dem82 [27]
20.8478066 (or 20.85%)
you do 480.77 minus 380.54 and it comes out to 100.23 and then you do 100.23/480=x/100 (discount/original=percent/100) and you multiply 100.23 by 100 and it comes to 10023 and you do 10023 divided by 480.77 and it comes out to 20.8478066 or 20.85%
6 0
3 years ago
How are exponential functions related to logarithmic functions?<br> Model that with an example.
scoundrel [369]
Exponential functions are related to logarithmic functions in that they are inverse functions. Exponential functions move quickly up towards a [y] infinity, bounded by a vertical asymptote (aka limit), whereas logarithmic functions start quick but then taper out towards an [x] infinity, bounded by a horizontal asymptote (aka limit).
If we use the natural logarithm (ln) as an example, the constant "e" is the base of ln, such that:
ln(x) = y, which is really stating that the base (assumed "e" even though not shown), that:
{e}^{y}  = x
if we try to solve for y in this form it's nearly impossible, that's why we stick with ln(x) = y
but to find the inverse of the form:
{e}^{y}  = x
switch the x and y, then solve for y:
{e}^{x}  = y
So the exponential function is the inverse of the logarithmic one, f(x) = ln x
3 0
3 years ago
Walter took out a $6,000 loan for six years. He is being charged 6 percent interest, compounded annually. Calculate the total am
cluponka [151]

Answer:

  $8511.11

Step-by-step explanation:

Each year, the amount Walter owes is multiplied by 1.06, so at the end of 6 years, Walter owes 1.06^6 times the amount he borrowed.

  he will pay $6,000×1.06^6 ≈ $8511.11

_____

At the end of the first year, Walter owes the original loan amount plus 6% interest. That total is ...

  $6000 + 0.06×6000 = $6000×1.06

At the end of the following year, he owes 1.06 times that amount, or ...

  6000×1.06²

The amount owed is multiplied by 1.06 each year until Walter pays off the loan.

8 0
3 years ago
Use the given values to complete to each table.<br> PLEASE HELP.
3241004551 [841]
I don’t know honestly
3 0
3 years ago
Read 2 more answers
X/2-14=-20 I tried on this one but I failed.
KengaRu [80]

Answer: I’m not going to tell u the answer hrhrhehehehehehrhehsnheaj

Step-by-step explanation:

-34 answer

6 0
3 years ago
Read 2 more answers
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