<span>Ending Amt = Bgng Amt * e ^-0.03t
In this equation, the "-0.03" is the decay factor or "k"
We can now solve for half-life by this equation:
</span>t = <span>(<span>ln [y(t) ÷ a]<span>)<span> ÷ -k (we can say beginning amount = 200 and ending amount = 100
</span></span></span></span>t = <span>(<span>ln [200 ÷ 100]<span>)<span> ÷ -k
</span></span></span></span>t = <span>(<span>ln [2]<span>)<span> ÷ -k
</span></span></span></span>t = 0.69314718056<span> ÷ --.03
t =</span><span><span><span> 23.1049060187
</span>
about 23 years
</span></span>
6 or should be I really don’t know
Answer:
471.24
Step-by-step explanation:
V=πr2h/3
radius = 5 and length = 18
answer = 471.24
please mark me brainliest!!
Answer:
Option A, Option B and option D
Step-by-step explanation:
㏒₂ 72 - ㏒₂ 3 = ㏒₂ (72 ÷ 3)
= ㏒₂ 24
2 ㏒₂ 2 + log₂ 6 = log₂ 2² + log₂ 6
= log₂ 4 + log₂ 6
= log₂ (4*6)
= log₂ 24
log₂ 6 + log₂ 4 = log₂ (6*4)
= log₂ 24