Option C: the electrons are embedded in a positive sphere.
As we know that was a wrong model and nowadays the electrons are considered to be around the nucleus, in regions called orbitals.
According to the calculation, set I is both the most accurate and most precise.
Exactness is a quality or state of being precise. 2a: comparison accuracy sense: the degree of precision with which an action is carried out or a measurement expressed 2b. The novel was fact-checked for historical authenticity. 2a: conformance to truth, to a standard, or to a model: exactness It is impossible to estimate the number of casualties with accuracy. Let's calculate the precision for the fourth set, considering
Δ1 = ∣(8.41−8.56)∣ g=0.15 g
Δ2 = (8.72−8.56) g=0.16 g
Δ3 = ∣(8.55−8.56)∣ g=0.01 g
Therefore: 
Learn more about accuracy and precision here:
brainly.com/question/28289139
#SPJ4
Hi
The volume is 58.1
The moler mass is 10.8
Molar mass details
10.81B (1*10.81)
Hope this helps
Answer:
I believe 11 is B 12 is C 13 is B and 14 is C
The central iodine atom in triiodide has sp3d hybridization.In triiodide anion, the central iodine atom has three equatorial lone pairs of electrons and the terminal iodines are bonded axially in a linear shape. Electrons in sp3d hybridization are arranged in trigonal bipyramidal symmetry.
Explanation:
When you draw the Lewis structure of this particle, you'll realize that the central I atom has a pair of bonds and three individual pairs of electrons. as a result of there are five things around that central I atom, it's<span> sp3d hybridized.
</span>
The bonds during a gas<span> (CH4) molecule </span>are fashioned<span> by four separate </span>however<span> equivalent orbitals; </span>one<span> 2s and </span>3<span> 2p orbitals of the carbon </span>interbreed<span> into four sp3 orbitals. </span>within the<span> ammonia molecule (NH3), 2s and 2p orbitals </span>produce<span> four sp3hybrid orbitals, </span>one among that<span> is occupied by a lone </span>try<span> of electrons.</span><span>
</span>
