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3 years ago

Which statement accurately describes the chemical symbol of an element?

Chemistry

2 answers:

Softa [21]3 years ago

8 0

Answer:

The chemical symbol always begins with a capital letter.

Explanation:

Aneli [31]3 years ago

7 0

Answer:

Explanation:

The chemical symbol of an element always starts with an chemical letter so here the answer is that the chemical symbol always begins with a capital letter.

It can be seen in the different elements chemical symbol .

For example, Tin is having chemical symbol as Sn while lead is having chemical symbol as Pb.

In both these elements, the chemical symbol starts with a capital letter but none of these have their symbol starts with same letter as their name.

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If one jellybean weighs 0.350g how many jelly beans are in 504g of jellybeans?

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Answer:

1440g

Explanation:

Divide 504g by 0.350g

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2 years ago

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Georgia [21]

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Explanation:

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3 years ago

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Explaination :

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2 years ago

Read 2 more answers

Determine the number of atoms that are in 1.15 mol of Cl 2.

Brums [2.3K]

Answer:

Explanation: I think its 4.91 x 10^25. Im not very sure, i just multipled 1.15 mol by the molar mass of Cl 2, which was 70.9 g. Then I multiplied that by avogadro's number. sorry if im wrong

4 0

2 years ago

Hello, everyone!

marusya05 [52]

Answer: 27.09 ppm and 0.003 %.

First, for air pollutants, ppm refers to parts of steam or gas per million parts of contaminated air, which can be expressed as cm³ / m³. Therefore, we must find the volume of CO that represents 35 mg of this gas at a temperature of -30 ° C and a pressure of 0.92 atm.

Note: we consider 35 mg since this is the acceptable hourly average concentration of CO per cubic meter m³ of contaminated air established in the "National Ambient Air Quality Objectives". The volume of these 35 mg of gas will change according to the atmospheric conditions in which they are.

So, according to the law of ideal gases,

PV = nRT

where P, V, n and T are the pressure, volume, moles and temperature of the gas in question while R is the constant gas (0.082057 atm L / mol K)

The moles of CO will be,

n = 35 mg x $\frac{1 g}{1000 mg}$ x $\frac{1 mol}{28.01 g}$

→ n = 0.00125 mol

We clear V from the equation and substitute P = 0.92 atm and

T = -30 ° C + 273.15 K = 243.15 K

V = $\frac{0.00125 mol x 0.082057 \frac{atm L}{mol K} x 243 K}{0.92 atm}$

→ V = 0.0271 L

As 1000 cm³ = 1 L then,

V = 0.0271 L x $\frac{1000 cm^{3} }{1 L}$ = 27.09 cm³

Then the acceptable concentration c of CO in ppm is,

c = 27 cm³ / m³ = 27 ppm

To express this concentration in percent by volume we must consider that 1 000 000 cm³ = 1 m³ to convert 27.09 cm³ in m³ and multiply the result by 100%:

c = 27.09 $\frac{cm^{3} }{m^{3} }$ x $\frac{1 m^{3} }{1 000 000 cm^{3} }$ x 100%

c = 0.003 %

So, the acceptable concentration of CO if the temperature is -30 °C and pressure is 0.92 atm in ppm and as a percent by volume is 27.09 ppm and 0.003 %.

5 0

2 years ago