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stira [4]
3 years ago
12

As a project manager of Permagam Construction you want to plan renting a fleet of 25 cu yd tractor-scrapers and have them haulin

g between the pit and a road construction job. The haul road is a rutted dirt road that deflects slightly under the load of the scraper. There is a slight grade of 5% from the pit at the fill location. The return road is level. The haul distance to the dump location is 0.90 miles and the return distance is 0.75 miles. The scrapers are push loaded in the pit. The cycle time for the pusher is 1.5 minutes and the cycle time for the scrapers is 8 minutes. Assume that the weight on the wheels is 75 tons (full) and 50 tons
(empty). (Use Tables 14.1 and 14.2)

What are the rolling resistances and grade resistance?

What are the effective grades?

How many scrapers you recommend to be rented? Explain.

What is the production of the system in case 4 scrapers would be rented?

Engineering
1 answer:
dlinn [17]3 years ago
7 0

Answer:

See explaination

Explanation:

Rolling resistance which in some occassions can be called rolling friction or rolling drag, is the force resisting the motion when a body rolls on a surface.

In order to calculate our rolling resistance, there should be a force.

Please kindly check attachment for the step by step solution of the given problem.

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When a welder must certify for their appropriate welder's certifications, all of the samples are basically flat work. Simple tack welds to deep fill welds are required.

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Read 2 more answers
A worker's hammer is accidentally dropped from the 20th floor of a building under construction. With what velocity does it strik
Illusion [34]

Answer:

Final Velocity (Vf)= 139.864 ft/s

Time (t)= 4,34 s

Explanation:

This is a free fall problem, to solve it we will apply free  fall concepts:

In a free fall the acceletarion is gravity (g) = 9,81 m/s2, if we convert it to ft/s^2 = g= 32.174 ft/s^2

  • Final velocity is Vf= Vo+ g*t[tex]Vf^{2} = Vo^{2} +2*g*h

where h is height (304 ft in this case).

Vo =0 since the hammer wasn't moving when it stared to fall

Then Vf^2= 0 + 2* 32.174 ft/s^2 *304 ft

          Vf^2= 19,561.8224  ft^2/s^2

          Vf=[sqrt{19561.8224 ft^2/s^2}

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Time t= (Vf-Vo)/g => (139.864 ft/s-0)/32.174 ft/s^2 = 4.34 sec

Good luck!

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3 years ago
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