do you mind rephrasing it in english
will
Answer:
(E) 0.71
Step-by-step explanation:
Let's call A the event that a student has GPA of 3.5 or better, A' the event that a student has GPA lower than 3.5, B the event that a student is enrolled in at least one AP class and B' the event that a student is not taking any AP class.
So, the probability that the student has a GPA lower than 3.5 and is not taking any AP classes is calculated as:
P(A'∩B') = 1 - P(A∪B)
it means that the students that have a GPA lower than 3.5 and are not taking any AP classes are the complement of the students that have a GPA of 3.5 of better or are enrolled in at least one AP class.
Therefore, P(A∪B) is equal to:
P(A∪B) = P(A) + P(B) - P(A∩B)
Where the probability P(A) that a student has GPA of 3.5 or better is 0.25, the probability P(B) that a student is enrolled in at least one AP class is 0.16 and the probability P(A∩B) that a student has a GPA of 3.5 or better and is enrolled in at least one AP class is 0.12
So, P(A∪B) is equal to:
P(A∪B) = P(A) + P(B) - P(A∩B)
P(A∪B) = 0.25 + 0.16 - 0.12
P(A∪B) = 0.29
Finally, P(A'∩B') is equal to:
P(A'∩B') = 1 - P(A∪B)
P(A'∩B') = 1 - 0.29
P(A'∩B') = 0.71
I can't resist helping someone with magic <span>(ﾉ◕ヮ◕)ﾉ*:･ﾟ✧
The formula for the volume of a cylinder is pi x r^2 x h.
That's 10240 x pi or 3</span><span>2169.91
</span>(ﾉ◕ヮ◕)ﾉ*:･ﾟ✧ woosh you now have smol pener
Answer:
Step-by-step explanation:
A triangle is isosceles if it has two equal sides and two equal angles.
From the diagram, the two perpendicular bisectors divides each base angle into 2 equal parts.
Since the 2 lines of the the perpendicular bisectors cuts across the midpoint of the triangle, it divides both lines JL and LK equally.
This means that lines JL and LK are equal.
Triangle JLK has 3 sides, JL, LK and JK.
Since lines JL and LK are equal, then
Triangle JLK is isosceles since it has two equal sides and 2 equal angles
Answer:
The correct answer is option C.
The mid point of the line segment.
Step-by-step explanation:
the perpendicular line segment construction twice using paper folding
we have to find the mid point of the given line segment.
We get the midpoint easily when fold the paper correctly
Therefore the correct answer is option C.
The mid point of the line segment.
