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188m - 556m is the wavelength range for AM radio.
2.77 - 3.40m is the wavelength range for FM radio.
1) For AM radio
f(max) = 1600 × 10³ Hz
f(min) = 540 ×10³Hz
c = fλ
λ = c/f where,
c = speed of light
f = frequency
λ= wavelength
So,
λ(min) = 3 × / 1600 × 10³ = 188 m
λ(max) = 3 × 10⁸/540 ×10³ = 556 m
So wavelength range of AM radio is 188 m - 556m
2) For FM radio
f(max) = 108 × 10⁶ Hz
f(min) = 88 × 10⁶ Hz
λ(min) = 3 × 10⁸ / 108 × 10⁶ = 2.77 m
λ(max) = 3 × 10⁸ / 88 × 10⁶ = 3.40 m
So wavelength range of FM radio is 2.77m - 3.40m
Learn more about frequency here brainly.com/question/10728818
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Answer:
4186 Joules
Explanation:
The specific heat capacity of a substance is defined as the amount of heat needed to raise the temperature of 1 kg of the substance by 1 Kelvin. In formula,
where
Q is the amiunt of heat needed
m = 1 kg is the mass
is the variation of temperature of the substance
For water, the specific heat capacity is . This means that the heat energy required to raise 1 kg of water by 1 K is exactly 4186 J.