Answer:
12 V, 0.5 A
Explanation:
For the Voltage,
Using,
Vs/Vp = Ns/Np.......................... Equation 1
Where Vs = Voltage in the secondary coil, Vp = Voltage in the primary coil, Ns = number of turn in the secondary coil, Np = number of turns in the primary coil.
Make Vs the subject of the equation
Vs = Vp(Ns/Np)........................ Equation 2
Given: Vp = 120 v, Np = 1000 turns, Ns = 100 turns
Substitute into equation 2
Vs = 120(100/1000)
Vs = 120×0.1
Vs = 12 v
For the current,
Using
Ns/Np = Ip/Is....................... Equation 3
Where Ip = current in the primary coil, Is = current in the secondary coil
make Is the subject of the equation
Is = Ip(Np/Ns).................. Equation 4
Given: Np = 1000 turns, Ns = 100 turns, Ip = 0.05 A
Substitute into equation 4
Is = 0.05(1000/100)
Is = 0.05×10
Is = 0.5 A.
Hence the voltage and the current in the secondary coil is 12 V, 0.5 A
