The position of the particle is given by:
x(t) = t³ - 12t² + 21t - 9
Differentiate x(t) with respect to t to find the velocity x'(t):
x'(t) = 3t² - 24t + 21
Differentiate x'(t) with respect to t to find the acceleration x''(t):
x''(t) = 6t - 24
What your saying doesn't make sense.
The picture shows it has a real life something to display conservation of energy with kinetic energy and potential energy.
Five sentences are for potential and kinetic energy. Potential energy is to energy an object when it stores. Kinetic energy is something to motion. When the potential energy is slows down the potential energy it might be increases. As from the object when the speeds up and it is decreases to potential energy.
Kinetic energy is to calculated by KE= mass×velocity²/2 as a fraction.
Potential energy is to calculated by PE= mass×g×height.
And the another picture it has a <span>energy, kinetic energy, mechanical energy, conservation of energy.
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For the part a) we need only the momentum of the box and we have the data to find it.
Momentum is given by,

where clearly, p is the momentum, m the mass of the box and v is the velocity.
Substituting,

For part b) we need an analysis of the situation. We understand that the box on a surface that has no friction will continue to rotate at the same speed previously defined. The box can only stop with friction, so,

<em>It is the same that part a)</em>