Answer: 244.05 J
Explanation:
To find speed at 30 m above the ground use equation:
V²=Vo²-2Gs
V0=31.4m/s
s=30m
G=9.81m/s²
-----------------------
V²=31.4²-2*9.81*30
V²=985.96+588.6
V²=1574.56
V=39.68m/s ---speed of arrow on 30 m obove the ground
Use equation for kinetic enrgy:
Ke=mV²/2
m=0.155kg
V=39.68m/s
-------------------------
Ke=0.155kg*(39.68m/s)²/2
Ke=0.155*1574.5/2
Ke=244.05J
Answer:
force on the wire of section cm will be 
Direction of force on the wire will be in south direction
Explanation:
We have given current in the wire i = 1 A
Magnetic field strength B = 0.6 T
We have to find the force on 1 cm section of the wire so l = 1 cm = 0.01 m
Force on the wire containing current is equal to


So force on the wire of section cm will be 
Direction of force on the wire will be in south direction
Answer:
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Explanation:
Answer:
The maximum height of the ball is 2 m.
Explanation:
Given that,
Mass of ball = 50 g
Height = 1.0 m
Angle = 30°
The equation is

We need to calculate the velocity
Using conservation of energy

Here, ball at rest so initial kinetic energy is zero and at the bottom the potential energy is zero

Put the value into the formula

Put the value into the formula




We need to calculate the maximum height of the ball
Using again conservation of energy

Here, h = y highest point
Put the value into the formula



Put the value of y in the given equation




Hence, The maximum height of the ball is 2 m.
Answer:
Efficiency of machine=4.9
Explanation:
We are given that
Mass of load=100 kg
Effort=20 N
Velocity ratio=10
We have to find the efficiency of machine.
Load=
Efficiency=
Using the formula
Efficiency of machine=
Efficiency of machine=
Efficiency of machine=4.9