The correct answer is good architecture is
The answer is 52.79 m.
I used this formula to get the formula for Vy:
v^2=vi^2+2(a)(x)
And got
Vy=square root (19.6 h)
Then I used that and put it in this formula:
tan(65) =Vy/Vx
tan(65) = square root (19.6 h)/15.0
Then I rearranged it to:
h=[(15.0)(tan65)]/19.6
h=52.79 m
Using the velocity-time graph, the displacement can be calculated by the area under the velocity-time graph. At 3 seconds the total displacement is then equal to (4)(2) + (4 + 2)*1/2 = 11 m. Assuming that the starting point is at x = 0, then the particle at t=3s is at x=11 m.
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Something hot like a fire , an eye of a stove , and the sun
Explanation:
The given data is as follows.
F = 
q = 
v = 385 m/s
= 0.876
Now, we will calculate the magnitude of magnetic field as follows.
B = 
= 
= 
T
= 10.65 T
Thus, we can conclude that magnitude of the magnetic field is 10.65 T.
