Answer:
There are 5 main conditions of the alveoli for proper gaseous exchange to in the lungs.
Explanation
Alveoli is found in the lungs of mammals, birds and reptiles. It is the part of the lungs where gaseous exchange really occurs.
Alveoli has a shape of that of balloon but indeed smaller than the real balloon. It allows the passage of oxygen and carbon dioxide
The five main conditions includes:
- The Alveoli must have large surface to volume ratio which increase the gases that could be exchanged
- The wall must be thin. This can shorten diffusion distance.
- Alveoli must be very moist so that oxygen and carbon dioxide can pass through the solution
- Alveoli must be well supplied with blood
- Alveoli must be permeable
The correct answer to the question above is The third Option: C; ultrasound imaging of the liver. The ultrasound imaging of the liver is definitely not an application of Doppler technology.
Hope this helps! :)
Current would increase <span>proportionally to voltage. </span><span> Power dissipation (heating) would increase with the square of the voltage. And resistance means, "</span><span>the refusal to accept or comply with something"</span>
Answer:
3.15m³
Explanation:
To solve this problem, let us first find the mass of the petrol from the given dimension.
Mass = density x volume
Volume of petrol = 4.2m³
Density of petrol = 0.3kgm⁻³
Mass of petrol = 4.2 x 0.3 = 1.26kg
So;
We can now find the volume of the alcohol
Volume of alcohol = 
Mass of alcohol = 1.26kg
Density of alcohol = 0.4kgm⁻³
Volume of alcohol = 
= 3.15m³
Answer:
largest lead = 3 m
Explanation:
Basically, this problem is about what is the largest possible distance anchorman for team B can have over the anchorman for team A when the final leg started that anchorman for team A won the race. This show that anchorman for team A must have higher velocity than anchorman for team B to won the race as at the starting of final leg team B runner leads the team A runner.
So, first we need to calculate the velocities of both the anchorman
given data:
Distance = d = 100 m
Time arrival for A = 9.8 s
Time arrival for B = 10.1 s
Velocity of anchorman A = D / Time arrival for A
=100/ 9.8 = 10.2 m/s
Velocity of anchorman B = D / Time arrival for B
=100/10.1 = 9.9 m/s
As speed of anchorman A is greater than anchorman B. So, anchorman A complete the race first than anchorman B. So, anchorman B covered lower distance than anchorman A. So to calculate the covered distance during time 9.8 s for B runner, we use
d = vt
= 9.9 x 9.8 = 97 m
So, during the same time interval, anchorman A covered 100 m distance which is greater than anchorman B distance which is 97 m.
largest lead = 100 - 97 = 3 m
So if his lead no more than 3 m anchorman A win the race.
