Answer:
The source is at a distance of 4.56 m from the first point.
Solution:
As per the question:
Separation distance between the points, d = 11.0 m
Sound level at the first point, L = 66.40 dB
Sound level at the second point, L'= 55.74 dB
Now,
where
I = Intensity of sound
Now,
Similarly,
Now,
Solving the above quadratic eqn, we get:
R = 4.56 m
A :-) F = mv^2 by t
Given - m = 10 kg
r = 10 m
v = 10 m/s
Solution -
F = mv^2 by t
F = 10 x 10^2 by 10
F = 10 x 100 by 10
( cut 10 and 10 because 10 x 1 = 10 )
F = 100 N
.:. The centripetal force is 100 N
For this case we have the following equation:
h (t) = -16t ^ 2 + 36t + 36
By the time the rock hits the water we have:
-16t ^ 2 + 36t + 36 = 0
Solving the second degree polynomial we have:
t1 = -3/4
t2 = 3
We discard the negative root because we want to find the time.
Answer:
It will take for the rock to hit the water about:
t = 3 seconds
There are many factors that increase the rate of reaction like concentration of reactants, atmosphere, presence or absence of catalyst, nature of reactants etc.
The factor usually does not increase the rate of reaction is lowering the temperature. But if we increase the temperature during reaction may be it increase the rate of reaction.
Answer:
d. 0V
Explanation:
The magnitude of four point charges are +3q, -q, +2q and -4q. I think you forget to mention the signs.
As we know that the potential due to the point charge that has traveled the distance d can be represented mathematically as,
= 1/4λε = 9× Nm²/C²
Now as it is mentioned in the question that all four charges are arranged in the corners of a square so there distance from the center is same. We can rewrite the above potential equation as follows.
(1)
We can find out d by the pythagoras theorem, as we are dealing with square so d is a semi diagonal.
by putting all values in equation (1)
V =
V = 0V