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Veronika [31]
2 years ago
12

A spring with a spring constant of 34 N/m is stretched 14 m. What is the energy stored in the

Physics
2 answers:
ehidna [41]2 years ago
8 0

Answer:

Elastic potential energy

Elastic potential energy is stored in the spring. Provided inelastic deformation has not happened, the work done is equal to the elastic potential energy stored.

Explanation:

becuse

iris [78.8K]2 years ago
3 0

Answer:10

Explanation:

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A block–spring system vibrating on a frictionless, horizontal surface with an amplitude of 7.0 cm has an energy of 14 J. If the
Bingel [31]

Answer:

E_T= 28J

Explanation:

The energy of Mass-Spring System the sum of the potential energy of the block plus the kinetic energy of the block:

E_T=U+K=\frac{1}{2} k \Delta x^2+\frac{1}{2} mv^2

Where:

\Delta x=Amplitude\hspace{3}or\hspace{3}d eformation\hspace{3} of\hspace{3} the\hspace{3} spring\\m=Mass\hspace{3}of\hspace{3}the\hspace{3}block\\k=Constant\hspace{3}of\hspace{3}the\hspace{3}spring\\v=Velocity\hspace{3}of\hspace{3}the\hspace{3}block

There are two cases, the first case is when the spring is compressed to its maximum value, in this case the value of the kinetic energy is zero, since there is no speed, so:

E_T=\frac{1}{2} k \Delta x^2\\\\14=\frac{1}{2} k7^2\\\\Solving\hspace{3} for\hspace{3} k\\\\k=\frac{28}{49} =\frac{4}{7}

The second case is when the block passes through its equilibrium position, in this case the elastic potential energy is zero since \Delta x=0, so:

E_T=\frac{1}{2} mv^2\\\\14=\frac{1}{2} mv^2\\\\Solving\hspace{3} for\hspace{3} v\\\\v^2=\frac{28}{m}

Now, let's find the energy of the system when the block is replaced by one whose mass is twice the mass of the original block using the previous data:

E_T=U+K=\frac{1}{2} k \Delta x^2+\frac{1}{2} m_2v^2

Where in this case:

m_2=New\hspace{3}mass=Twice\hspace{3} the\hspace{3} mass \hspace{3}of\hspace{3} the\hspace{3} original=2m

Therefore:

E_T=\frac{1}{2} (\frac{4}{7} ) (7^2)+\frac{1}{2} (2m)(\frac{28}{m_2})=\frac{1}{2} (\frac{4}{7} ) (7^2)+\frac{1}{2} (2m)(\frac{28}{2m})=14+14=28J

8 0
3 years ago
If the velocity of an object is changing, its momentum is also changing. please select the best answer from the choices provided
Dmitry [639]
The answer is true

I hope this helps
3 0
3 years ago
Read 2 more answers
A student claims that when two bodies not initially in thermal equilibrium are placed in contact, the rise in temperature of the
zimovet [89]

Answer:

Explanation:

No.

There is a difference between energy, called heat in this case, and temperature, which is a measure of the amount of heat contained in a material and is dependent on the material properties.

Temperature difference is what causes heat to move from one body to another.

Two objects at different temperatures placed in contact with one another will cause heat to move from the warmer body to the colder body until the temperature difference is eliminated.

The amount of heat leaving the warmer body will exactly equal the amount of heat absorbed by the cooler body. (assuming isolated system of two bodies) The temperature change within each of those bodies could be vastly different.

Example would be a 2 mm bead of molten lead dropped into a liter glass of tap water. The lead may cool several hundred °C as it solidifies while the water temperature would increase less than 1 °C

3 0
2 years ago
A soccer player heads the ball and sends it flying vertically upwards at a speed of 18.0 m/s . How high above the players ' head
Irina-Kira [14]

Answer:

16.53 m

Explanation:

The following data were obtained from the question:

Initial velocity (u) = 18.0 m/s.

Final velocity (v) = 0 m/s

Acceleration due to gravity (g) = 9.8 m/s²

Maximum height (h) =.?

The maximum height reached by the ball can be obtained as follow:

v² = u² – 2gh (since the ball is going against gravity)

0² = 18² – (2 × 9.8 × h)

0 = 324 – 19.6h

Rearrange

19.6h = 324

Divide both side by 19.6

h = 324 / 19.6

h = 16.53 m

Therefore, the maximum height reached by the ball is 16.53 m

6 0
3 years ago
A student constructs a simple constant volume gas thermometer and calibrates it using the boiling point of water, 100°C, and the
just olya [345]

Answer:

The pressure corresponding to the absolute zero temperature is 0.997atm.

Explanation:

To solve this question, you draw a straight vertical line with the boiling point temperature and pressure on top of the line and the freezing point temperature and pressure on the lower part. The absolute temperature somewhere in the middle of the line with the pressure to be obtained.

So, we have;

0- (-19) / 100 - (-19) = P - 0.9267 / 1.366 - 0.9267

19 / 119 = P - 0.9267 / 0.4393

Cross multiply, we have

19 * 0.4393 = 119(P -0.9267)

8.3467 = 119P - 110.2773

119P = 118.624

P = 0.997 atm

So at 0°C, the pressure of the thermometer is 0.997atm.

4 0
3 years ago
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