(I think you have a mistake in your question as the addition is 30mL, not 100mL)
when PH = - ㏒[H+]
and here we have HClO4 is the strong acid
So PH = - ㏒[HClO4]
moles of HClO4 = 0.1 L *0.18 m = 0.018 M
moles of LiOH = 0.03 L * 0.27 m = 0.0081 M
when the total volume = 0.1L + 0.03L = 0.13 L
∴ [HClO4] = (0.018-0.0081)/0.13 L
= 0.076 M
PH = -㏒ 0.076
= 1.12
B. is positive
H20 (l)--> H20 (g)
when that happens, the heat is absorbed into the liquid to change the state of the liquid to gas; therefore, in order to change to a gaseous state, heat must be a reactant. and so enthalpy is increasing
Answer is 2.25 mol.
<em>Explanation;</em>
The balanced reaction equation is
2KMnO₄ + 5H₂O₂ + 3H₂SO₄ → K₂SO₄ + 2MnSO₄ + 8H₂O + 5O₂
The stoichiometric ratio between KMnO₄ and H₂O₂ is 2 : 5.
Hence,
moles of reacted H₂O₂ = moles of KMnO₄ reacted x (5/2)
= 0.90 mol x (5/2)
= 2.25 mol
Hence, your answer is correct.
C. flammable
let me know if you want to know why
Answer:
B. False
Explanation:
The correct fluid is intracellular. (inside cells)
Extracellular contains 1/3 of the body's water. (outside cells)