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AURORKA [14]
3 years ago
10

Choose a reasonable explanation to account for the differences. There may be more than one possible reason that makes sense, jus

t select one of them.
A. It is possible not all of the water was evaporated from the sand, causing the recovered mass to be higher.
B. It is possible not all of the water was evaporated from the sand, causing the recovered mass to be lower.
C. While drying the NaCl, the liquid boiled and some splattered out of the evaporating dish, causing the recovered mass to be lower
D. While drying the NaCl, the liquid boiled and some splattered out of the evaporating dish, causing the recovered mass to be higher.
E. There was no difference in recovered and original mass, so there is no difference to account for.
Chemistry
1 answer:
Ugo [173]3 years ago
6 0

Answer:

A. It is possible not all of the water was evaporated from the sand, causing the recovered mass to be higher

D. While drying the NaCl, the liquid boiled and some splattered out of the evaporating dish, causing the recovered mass to be higher.

Explanation:

Sand absorbs water and stores it. The sunlight causes the water to evaporate but sand can hold some of the water inside it. This results in increase in mass of the sand. The mass of sand before and after the water evaporation can be different.

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If you are calculating the grams to mL ratio, you are trying to find the object’s…
Alex

Answer:

Density

Explanation:

The ratio of mass to the volume of an object is called its density. Unit of mass is grams and that of volume is mL.

Density = mass/volume

\text{Density}=\dfrac{\text{grams}}{\text{mL}}\\\\=\text{grams/mL}

If you are calculating the grams to mL ratio, it means that we are trying to find the object's density.

4 0
3 years ago
Which spectroscopic tool would be best for distinguishing a sample of 1,2,2-tribromopropane from 1,1,2-tribromopropane?
12345 [234]

1-H NMR spectroscopy tool will be used for distinguishing a sample of 1,2,2-tribromopropane from 1,1,2-tribromopropane.

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It can be calculated by simply counting the number of unique hydrogens on one side of the symmetry plane will give you the count of signals individual molecules emit in a 1H NMR spectrum.

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5 0
2 years ago
If 25.5g of sodium thiosulphate was dissolved in 40g of distilled water at 25°C,
zhenek [66]

Answer:

Formula: Na2S2O3

we get solubility.

Divide the mass of the compound by the mass of the solvent and then multiply by 100 g to calculate the solubility in g/100g .

Solution given:

mass of sodium thiosulphate [m1]=25.5g

mass of water [m2]=40g

at temperature [t]=25°C

we have

<u>solubility in g/dm^3</u> :\frac{solute in gram}{solvent in gram} *100

  • =\frac{25.5}{40}*100
  • =63.75g /litre=63.75g/dm³

<u>solubility in g/dm^3 :63.75g/dm³</u>

<u>n</u><u>o</u><u>w</u>

solubility of the solute in mol/dm^3=:63.75g/dm³/178=0.4 mol/dm³

6 0
3 years ago
What is the concentration of 10.00 mL of HBr if it takes 16.73 mL of a 0.253 M LiOH solution to neutralize it?
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First. let's write the reaction formula: HBr +LiOH ----> LiBr + H₂O

let's get the moles of LiOH first

moles= Molarity x Liters

moles= 0.253 M x 0.01673 Liter= 0.00423 moles LiOH

using the balanced equation, you can see that 1 mol LiOH is equal to 1 mol HBr. so:

0.00423 mol LiOH = 0.00423 mol HBr

now let's find the concentration

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3 0
4 years ago
Quick question plz . .....Which one of the following is acidic oxide?
dedylja [7]

Answer:

B

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8 0
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