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2 years ago

Why are alloys more useful than pure metals?

Chemistry

1 answer:

makkiz [27]2 years ago

7 0

Answer:

Alloys are more useful than pure metals because they contain multiple element containing at least one metal. Answer: The properties of alloys are often superior to their component elements. ... Metals are ductile while ionic crystals are not.

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How many moles of carbon in 130g of C2H6

-BARSIC- [3]

7.22 moles of C2H6. Since there are 2 carbon atoms per C2H6, we must multiply the number of moles of C2H6 by 2 to get the number of moles of Carbon which is 14.4 or 14 if using two sig figs.

5 0

3 years ago

Read 2 more answers

A compound with molecular formula C6H9No that has an amide functional group and does not have an alkene group

Flauer [41]

Answer:

Following are the responses to the given question:

Explanation:

$\to C_6H_9NO$

calculating the HOI:

$= \frac{2C+2+N-H-X}{2} \\\\ =\frac{2\times 6+2+1-9-0}{2}\\\\ =\frac{12-6}{2}\\\\=\frac{6}{2}\\\\=3$

So, in the above compund there are three bounds or we can say that one is double and two bound is single.

Please find the attachment file of the Function group:

In the above given conditon compound doesn't include the alkene functional group that is absense of $-C=C-$ , and compound include $-C\equiv C-$ So, please find the attached file of the structure of the compound:

3 0

2 years ago

Be sure to answer all parts. Nitric oxide (NO) reacts with oxygen gas to form nitrogen dioxide (NO2), a dark brown gas: 2NO(g) +

notka56 [123]

Answer: NO is the limiting reagent in the given reaction and 0.857 moles of $NO_2$ will be produced.

Explanation:

Limiting reagent is defined as the reagent which is present in less amount and it limits the formation of products.

Excess reagent is defined as the reagent which is present in large amount.

For the given chemical reaction:

$2NO(g)+O_2(g)\rightarrow 2NO_2(g)$

We are given:

Moles of NO = 0.857 mol

Moles of oxygen = 0.498 mol

By stoichiometry of the reaction:

If 2 moles of NO reacts with 1 mole of oxygen gas.

So, 0.857 moles of NO will react with = $\frac{1}{2}\times 0.857=0.4285mol$ of $O_2$

As, the given amount of oxygen gas is more than the required amount. So, it is considered as an excess reagent.

Thus, NO is considered as the limiting reagent because it limits the formation of products.

By Stoichiometry of the reaction:

If 2 moles of NO produces 2 moles of nitrogen dioxide gas.

So, 0.857 moles of NO will produce = $\frac{2}{2}\times 0.857=0.857mol$ of $NO_2$

Hence, NO is the limiting reagent in the given reaction and 0.857 moles of $NO_2$ will be produced.

6 0

3 years ago

What is the mass of 2.50L of SO2 gas at stp

maxonik [38]

STP is abbreviation for Standard Temperature and Pressure at which the temperature is 273 K and pressure is 1 atm
- At these conditions the molar volume is equal to 22.4 L
so 1 mole of SO₂ volume = 22.4 L
? mole of SO₂ volume = 2.5 L
number of moles = 2.5 / 22.4 = 0.1116 mol
mass of SO₂ = 0.1116 * 64.063 = 7.15 g

5 0

2 years ago

Read 2 more answers

An analytical chemist is titrating 118.3 mL of a 0.3500 M solution of butanoic acid (HC3H7CO2) with a 0.400 M solution of KOH. T

TEA [102]

Answer:

pH = 12.33

Explanation:

Lets call HA = butanoic acid and A⁻ butanoic acid and its conjugate base butanoate respectively.

The titration reaction is

HA + KOH ---------------------------- A⁻ + H₂O + K⁺

number of moles of HA : 118.3 ml/1000ml/L x 0.3500 mol/L = 0.041 mol HA

number of moles of OH : 115.4 mL/1000ml/L x 0.400 mol/L = 0.046 mol A⁻

therefore the weak acid will be completely consumed and what we have is the unreacted strong base KOH which will drive the pH of the solution since the contribution of the conjugate base is negligible.

n unreacted KOH = 0.046 - 0.041 = 0.005 mol KOH

pOH = - log (KOH)

M KOH = 0.005 mol / (0.118.3 +0.1154)L = 0.0021 M

pOH = - log (0.0021) = 1.66

pH = 14 - 1.96 = 12.33

Note: It is a mistake to ask for the pH of the acid solution since as the above calculation shows we have a basic solution the moment all the acid has been consumed.

4 0

2 years ago