A because for example in n=4 we have all of these sub levels 4s is completed sooner than 4p and so
The freezing point of the solvent in a solution changes as the concentration of the solute in the solution changes (but it does not depend on the identity of either the solvent or the solute(s) particles (kind, size or charge) in the solution).
Generally, pressures lower than 1 atmosphere lower the temperature at which a substance freezes, but for water, a higher pressure gives a lower freezing point. The force from a pressure change figures into the molecular forces already at play in a substance.
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1. Remember (sum of products) - (sum of reactants)
So ΔHrxn = 2 ΔHf [H2(g)] + ΔHf [Ca(OH)2(s)] - 2 ΔHf [H2O(l)] - ΔHf [Ca(s)]
= 2*0 + -986.09 kJ/mol - 2*(-285.8 kJ/mol) - 0
Do the math and you'll have the answer. BTW the ΔHf [H2(g)] and ΔHf
[Ca(s)] were 0 because these are elements in their standard states.
</span>HOPE THIS HELPS ;)
There is a key piece of information that we are missing.
we need the following:
Kb of water= 0.512
the change in boiling point (ΔTb) can be calculated using the following formula:
ΔTb= Kb x m
we already have Kb, but we need to determine the molality (m).
1) let's convert the grams of glucose to moles using the molar mass of it. The molecule formula of glucose is C₆H₁₂O₆.
molar mass C₆H₁₂O₆= (6 x 12.0) + (12 x 1.01) + (6 x 16.0)= 180 g/mol
2) let's determine the Kilograms of water.
info:
density of water= 1.0 g/ mL or 1 grams = 1 mL
1000 grams= 1 kilogram
3) let's plug in the values to solve for molality
finally, we can solve for change in boiling point.
ΔTb= Kb x m
ΔTb= (0.512) (0.545m)=
0.279°C
Sulphur dioxide is greenhouse gas
may this will help you