Answer:
Step-by-step explanation:
In a geometric sequence, the consecutive terms differ by a common ratio,r. Considering the given sequence,
r = 6/- 2 = - 18/6 = - 3
Therefore, the sequence is geometric.
The formula for determining the nth term of a geometric progression is expressed as
Tn = ar^(n - 1)
Where
a represents the first term of the sequence.
r represents the common ratio.
n represents the number of terms.
From the information given,
a = - 2
r = - 3
The explicit formula is
Tn = - 2 × (- 3)^(n - 1)
To find the 8th term, T8,
T8 = - 2 × (- 3)^(8 - 1)
T8 = - 2 × (- 3)^7
T8 = - 2 × - 2187
T8 = 4374
Wait hold on it should be C I think correct me if I'm wrong doe-
Answer:
c
Step-by-step explanation:
4x = 20
--------------
4
x = 5
*20 divided by 4 equals 5*
Answer:
v = 176
Step-by-step explanation:
Since a fraction is essentially the same thing as dividing one number by another, we can multiply 44 by 4, the denominator of the fraction we are finding the numerator for, and get 176. This fraction is already in negative form, so we don't need to do anything else.
Answer:
Funciones trigonométricas de μ
sen (μ) = b/ √(a^2+ b^2)
cos (μ) = a/ √(a^2+ b^2)
tan (μ) = b/ a
cot (μ) = a/ b
sec (μ) = √(a^2+ b^2) / a
csc (μ) = √(a^2+ b^2) /b
Step-by-step explanation:
Ya que no proportionaste el valor de cot μ podemos suponer un valor = a/b para que tengas una respuesta general y reemplaces el valor de a y b de acuerdo con tu caso.
cot (μ) = a/b
_______________________________
Funciones trigonométricas
sen (μ) = cateto opuesto/ hipotenusa
cos (μ) = cateto adyacente/ hipotenusa
tan (μ) = cateto opuesto/ cateto adyacente
cot (μ) = cateto adyacente/ cateto opuesto
sec (μ) = hipotenusa / cateto adyacente
csc (μ) = hipotenusa /cateto opuesto
cot (μ) = cateto adyacente/ cateto opuesto = cot (μ) = a/ b
Por lo tanto:
Cateto adyacente = a
Cateto opuesto = b
Hipotenusa
H^2 = Cateto adyacente^2 + Cateto opuesto^2
H= √(a^2+ b^2)
Reemplaznado los valores de los catetos y la hipotenusa se obteienen los valores de las funciones trigonométricas de μ.