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Brut [27]
2 years ago
11

Make x the subject of the formula x(a-b)=a(b-x).​

Mathematics
2 answers:
Anna35 [415]2 years ago
7 0

Answer:

{ \sf{x(a - b) = a(b - x)}}

Open the brackets:

{ \sf{ax - bx = ab - ax}} \\ { \sf{2ax - bx= ab }}

Factorise out x:

{ \sf{x(2a  - b) = ab}} \\ { \sf{x(2a - b) = ab}} \\ { \sf{x =  \frac{ab}{2a - b} }}

ddd [48]2 years ago
3 0

Answer:

Hello,

Step-by-step explanation:

x(a-b)=a(b-x)\\\\x(a-b)=ab-ax\\\\x(a-b)+ax=ab\\\\x(a-b+a)=ab\\\\x(2a-b)=ab\\\\\\x=\dfrac{ab}{2a-b} \ if\ 2a-b\neq 0

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The Wheel Shop sells other kinds of vehicles. There are bicycles and go-carts in a different room of the shop. Each bicycle has
const2013 [10]

Answer:

15 bicycle and 6 go-cart.

Step-by-step explanation:

Given that,  

There are a total of 21 seat and 54 wheels in the room.  

Assume there are x number of bicycle.  

Since, each bicycle has only one seat and each go-cart has only one seat.  

Then, the number of go-cart is (21-x)

There are two wheels in a bicycle.

Total number of wheel in x number of bicycle is = (2.x)=2x  

There are four wheels in a go-cart.  

Total number of wheel in (21-x) number of go-cart =4(21-x)  

According to the problem,  

2x+4(21-x)=54  

⇒2x+84-4x=54  

⇒2x-4x=54-84  

⇒ -2x=  -30  

\Rightarrow x=\frac{-30}{-2}

⇒x = 15  

Hence, there are 15 bicycle and (21- 15)=6 go-cart

5 0
3 years ago
8. Is this number correctly written in scientific notation? 6.875 x 10 yes O no​
Komok [63]

Answer:

No

Step-by-step explanation:

I believe you have to approximate or round it off.

that will be 6.9.

5 0
2 years ago
Which of the following number lines represents the compound inequality shown below?
OLEGan [10]

Answer:

I'm not really sure what the question might be asking or if I've been given all the information but this is how you would solve it as (-2,4] meaning any real number between these will give you a real x on the domain.

Step-by-step explanation:

-4 < 3x + 2 \leqslant 14 \\  - 6 < 3x \leqslant 12 \\  - 2 < x \leqslant 4

6 0
3 years ago
The brand manager for a brand of toothpaste must plan a campaign designed to increase brand recognition. He wants to first deter
JulsSmile [24]

Answer:

1) n=114

2) n=59

3) On this case no, because if we survey just the adults of the nearest college that would be a convenience sample. And when we use "convenience sample" we have some problems associated to bias. This methodology it's not appropiate in order to have a good estimation of the parameter of interest. It's better use a random, cluster or stratified sampling.

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 80% of confidence, our significance level would be given by \alpha=1-0.80=0.2 and \alpha/2 =0.1. And the critical value would be given by:

z_{\alpha/2}=-1.28, z_{1-\alpha/2}=1.28

Part 1

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.06 or 6% points, and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

Since we don't have a prior estimate of \het p we can use 0.5 as a good estimate, replacing into equation (b) the values from part a we got:

n=\frac{0.5(1-0.5)}{(\frac{0.06}{1.28})^2}=113.77  

And rounded up we have that n=114

Part 2

On this case we have a prior estimate for the population proportion and is \hat p =0.85 so replacing the values into equation (b) we got:

n=\frac{0.85(1-0.85)}{(\frac{0.06}{1.28})^2}=58.027

And rounded up we have that n=59

Part 3

On this case no, because if we survey just the adults of the nearest college that would be a convenience sample. And when we use "convenience sample" we have some problems associated to bias. This methodology it's not appropiate in order to have a good estimation of the parameter of interest. It's better use a random, cluster or stratified sampling.

5 0
3 years ago
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8 0
3 years ago
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