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eduard
3 years ago
8

How does the density of gas particles inside your tires compare with the density of gas particles in the air outside your tires

Physics
1 answer:
bixtya [17]3 years ago
4 0

Answer:

The density of gas particles inside tires is higher than the density of the gas particles outside.

Explanation:

Let suppose that both gas inside and outside tires behave ideally. The equation of state for ideal gases is presented below:

P\cdot V = n\cdot R_{u}\cdot T (1)

Where:

P - Pressure.

V - Volume.

n - Molar quantity.

R_{u} - Ideal gas constant.

T - Temperature.

By definition of molar quantity, we expand (1) into this form:

P\cdot V = \frac{m\cdot R_{u}\cdot T}{M}

And after some algebraic handling, we derive the following formula for the density of the gas:

\rho = \frac{P\cdot M}{R_{u}\cdot T} (2)

The gas inside tires has a pressure higher than the pressure outside, but the same temperature usually. Therefore, the density of gas particles inside tires is higher than the density of the gas particles outside.

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When the displacement in SHM is equal to 1/3 of the amplitude xm, what fraction of the total energy is (a) kinetic energy and (b
Nesterboy [21]

Answer:

Explanation:

Given

Displacement is \frac{1}{3} of Amplitude

i.e. x=\frac{A}{3} , where A is maximum amplitude

Potential Energy is given by

U=\frac{1}{2}kx^2

U=\frac{1}{2}k(\frac{A}{3})^2

U=\frac{1}{18}kA^2

Total Energy of SHM is given by

T.E.=\frac{1}{2}kA^2

Total Energy=kinetic Energy+Potential Energy

K.E.=\frac{1}{2}kA^2 -\frac{1}{18}kA^2

K.E.=\frac{8}{18}kA^2

Potential Energy is \frac{1}{8} th of Total Energy

Kinetic Energy is \frac{8}{9} of Total Energy

(c)Kinetic Energy is 0.5\times \frac{1}{2}kA^2

P.E.=\frac{1}{4}kA^2

\frac{1}{2}kx^2=\frac{1}{4}kA^2

x=\frac{A}{\sqrt{2}}                  

7 0
3 years ago
Read 2 more answers
The stopping sight distance for a car traveling at 50 mph is 461 ft (including both perception-reaction distance and braking dis
Ivan

Answer:

2.08 s

Explanation:

We are given that

Speed,v=50mph=73.3ft/s

1 mile=5280 feet

1 hour=3600 s

Distance,d=461 ft

t=2.5 s

v'=60 mph=88 ft/s

We have to find the perception reaction time.

Perception reaction distance=d_p=vt=73.3\ti es 2.5=183.25 feet

d_p=d'_p

d'_p=v't

t'=\frac{183.25}{88}=2.08 s

4 0
3 years ago
A 20,000 kg railroad car is traveling at 5 m/s when it collides and couples with a second, identical car at rest. What is the re
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Ok I don’t know the answer I’m in 5th grade but 2431 is wrong
7 0
3 years ago
Suppose you first walk 12.0 m in a direction 200 west of north and then 20.0 m in a direction 40.00 south of west. How far are y
Tpy6a [65]

Complete Question

The  complete question is shown on the first uploaded image

Answer:

the compass direction of the resultant displacement is  \theta  =4.7^o south of west

Explanation:

Generally using cosine we can obtain the resultant R as follows

     R^2  =  A^2  + B^2 -2ABcos(70)

=>   R  =  \sqrt{12^2  + 20^2  - 2(12 ) *  (20) cos  70}

=>    R  =  19.48 \  m

We can obtain the direction of the resultant by first  using sine rule to obtain angle C as follows

       \frac{A}{sin  C}  =  \frac{R}{sin70 }

=>    C=  sin ^{-1} [\frac{A *  (sin 70)}{R} ]

=>    C =  sin ^{-1} [\frac{20 *  (sin 70)}{19.48} ]

=>  C =  74.7 ^o

Then the direction is obtained as

       \theta  =  C  -  70

=>    \theta  = 74.7   -  70

=>     \theta  =4.7^o

Hence the compass direction of the resultant displacement is  \theta  =4.7^o south of west

7 0
3 years ago
An electric field of 1139 V/m is applied to a section of silver of uniform cross section. Find the resulting current density if
N76 [4]

Answer:

So, you're going to need the equation ρ = ρo [1 + α(T-To)]  

1.59x10^-8 ohms*m is your ρo because that is measured at your reference temperature (To), 20◦C. T is your 6◦C and α is 0.0038(◦C)−1. So, using that you solve for ρ. If you keep up with the units though, you notice it comes out to be ohms*m and that isn't what you want.  

So, the next equation you need is J=σE where E is your electric field (3026 V/m) and σ is the electrical conductivity which is the inverse of your answer you got in the previous equation. So find the inverse of that answer and multiply it by your electric field and that will give you the current density.  

I hope this helps!

Explanation:

8 0
3 years ago
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