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eduard
3 years ago
8

How does the density of gas particles inside your tires compare with the density of gas particles in the air outside your tires

Physics
1 answer:
bixtya [17]3 years ago
4 0

Answer:

The density of gas particles inside tires is higher than the density of the gas particles outside.

Explanation:

Let suppose that both gas inside and outside tires behave ideally. The equation of state for ideal gases is presented below:

P\cdot V = n\cdot R_{u}\cdot T (1)

Where:

P - Pressure.

V - Volume.

n - Molar quantity.

R_{u} - Ideal gas constant.

T - Temperature.

By definition of molar quantity, we expand (1) into this form:

P\cdot V = \frac{m\cdot R_{u}\cdot T}{M}

And after some algebraic handling, we derive the following formula for the density of the gas:

\rho = \frac{P\cdot M}{R_{u}\cdot T} (2)

The gas inside tires has a pressure higher than the pressure outside, but the same temperature usually. Therefore, the density of gas particles inside tires is higher than the density of the gas particles outside.

You might be interested in
What is the wavelength in nanometers of light when the energy is 1. 91 × 10^6 j for a mole of photons?.
JulijaS [17]

The wavelength in nanometers of light when the energy is 1. 91 × 10^6 j for a mole of photons is <u>62. 8 nm.</u>

Wavelength is the distance among the same points (adjacent crests) within the adjoining cycles of a waveform signal propagated in space or along a cord. In wi-fi structures, this period is typically specified in meters (m), centimeters (cm), or millimeters (mm).

The wavelength is the distance between wave crests, and it is going to be the same for troughs. The frequency is the variety of vibrations that skip over a given spot in one 2nd, and it's far measured in cycles consistent with the second (Hz) (Hertz).

Frequency is the ratio of pace and wavelength in relation to speed. In comparison, wavelength refers to the ratio of pace and frequency. Audible sound waves are characterized by way of a frequency range of 20 to 20 kHz. In contrast, the variety of wavelengths of visible light is from four hundred to seven hundred nm.

<u>calculation:-</u>

*E=hc/λ

1.91 × 10^6 J = (6.62610⁻³⁴) (3.00*10⁸) / λ

λ= (6.62610⁻³⁴) (3.00*10⁸) / 1.91 × 10⁶ J

λ= 1.0410⁻³¹× 10⁻⁹ × 6.022*10²³

 =<u> 62. 8 nm </u>

Learn more about wavelength here:-brainly.com/question/10728818

#SPJ4

6 0
1 year ago
What are the strength and direction of an electric field that will balance the weight of a 0.9 g plastic sphere that has been ch
Vladimir79 [104]
(a) The force exerted by the electric field on the plastic sphere is equal to
F=qE
where q=-3.4 nC=-3.4 \cdot 10^{-9} C is the charge of the sphere and E is the strength of the electric field. This force should balance the weight of the sphere:
F=mg =0.9 g
where m is the mass of the sphere and g is the gravitational acceleration.

Since the two forces must be equal, we have:
qE=mg
and so we find the intensity of the electric field
E= \frac{mg}{q}= \frac{0.9 \cdot 9.81 m/s^2}{3.4 \cdot 10^{-9} C} =2.6 \cdot 10^9 N/C

(b) Now let's find the direction of the field. The electric force must balance the weight of the sphere, which is directed downward, so the electric force should be directed upward. Since the charge is negative, the force is opposite to the electric field direction, and so the direction of the electric field is downward.
4 0
3 years ago
What do thermal energy and electrical energy have in common
Lubov Fominskaja [6]

Answer:

you can write some points its an explanation

and similarities. or common

Explanation:

Thermal energy refers to the energy contained within a system that is responsible for its temperature. Heat is the flow of thermal energy. A whole branch of physics, thermodynamics, deals with how heat is transferred between different systems and how work is done in the process (see the 1ˢᵗ law of thermodynamics).

The faster the atoms or molecules move, the more heat or thermal energy they have. ... A hair straightener turns the electrical energy from a wall outlet into heat (thermal energy). 4. As electricity runs through the filaments in a space heater, the electrical energy is converted into heat (thermal energy).

3 0
3 years ago
A disc of mass m slides with negligible friction along a flat surface with a velocity v. The disc strikes a wall head-on and bou
qwelly [4]

Answer:

-v/2

Explanation:

Given that:

  • a disc of mass m
  • Collides with the wall going through a sliding motion on on the plane smooth surface.
  • Upon rebounding from the wall its kinetic energy becomes one-fourth of the initial kinetic energy before collision.

<u>We know, kinetic energy is given as:</u>

KE_i=\frac{1}{2}. m.v^2

consider this to be the initial kinetic energy of the body.

<u>Now after collision:</u>

KE_f=\frac{1}{4}\times KE_i

KE_f=\frac{1}{4} \times \frac{1}{2}\times m.v^2

Considering that the mass of the body remains constant before and after collision.

KE_f=\frac{1}{2}\times m.(\frac{v}{2})^2

Therefore the velocity of the body after collision will become half of the initial velocity but its direction is also reversed which can be denoted by a negative sign.

3 0
3 years ago
A piston having 7.23 g of steam at 110°C increases its temperature by 35°C. At the same time it expands from a volume of 2.00 L
My name is Ann [436]

Answer : The value of q,w,\Delta U\text{ and }\Delta U is 505 J, -599 J, -94 J and -693 J respectively.

Explanation : Given,

Mass of steam = 7.23 g

Initial temperature = 110^oC

Final temperature = (110+35)^oC=145^oC

Initial volume = 2 L

Final volume = 8 L

External pressure = 0.985 bar

Heat capacity of steam = 1.996 J/g.K

First law of thermodynamic : It states that the energy can not be created or destroyed, it can only change or transfer from one state to another state.

As per first law of thermodynamic,

\Delta U=q+w

First we have to calculate the heat absorbed by the system.

Formula used :

Q=m\times c\times \Delta T

or,

Q=m\times c\times (T_2-T_1)

where,

Q = heat absorbed by the system = ?

m = mass of steam = 7.23 g

C_p = heat capacity of steam = 1.966J/g.K

T_1 = initial temperature  = 110^oC=273+110=383K

T_2 = final temperature  = 145^oC=273+145=418K

Now put all the given value in the above formula, we get:

Q=7.23g\times 1.966J/g.K\times (418-383)K

Q=505J

Now we have to calculate the work done.

Formula used :

w=-p_{ext}dV\\\\w=-p_{ext}(V_2-V_1)

where,

w = work done  = ?

p_{ext} = external pressure = 0.985 bar = 0.985 atm   (1 bar = 1 atm)

V_1 = initial volume of gas = 2.00 L

V_2 = final volume of gas = 8.00 L

Now put all the given values in the above formula, we get :

w=-p_{ext}(V_2-V_1)

w=-(0.985atm)\times (8.00-2.00)L

w=-5.91L.atm=-5.91\times 101.3J=-599J

conversion used : (1 L.atm = 101.3 J)

Now we have to calculate the change in internal energy of the system.

\Delta U=q+w

\Delta U=505J+(-599J)

\Delta U=-94J

Now we have to calculate the change in enthalpy of the system.

Formula used :

\Delta H=\Delta U+P\Delta V

\Delta H=\Delta U+w

\Delta H=(-94J)+(-599J)

\Delta H=-693J

Therefore, the value of q,w,\Delta U\text{ and }\Delta U is 505 J, -599 J, -94 J and -693 J respectively.

4 0
4 years ago
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