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eduard
3 years ago
8

How does the density of gas particles inside your tires compare with the density of gas particles in the air outside your tires

Physics
1 answer:
bixtya [17]3 years ago
4 0

Answer:

The density of gas particles inside tires is higher than the density of the gas particles outside.

Explanation:

Let suppose that both gas inside and outside tires behave ideally. The equation of state for ideal gases is presented below:

P\cdot V = n\cdot R_{u}\cdot T (1)

Where:

P - Pressure.

V - Volume.

n - Molar quantity.

R_{u} - Ideal gas constant.

T - Temperature.

By definition of molar quantity, we expand (1) into this form:

P\cdot V = \frac{m\cdot R_{u}\cdot T}{M}

And after some algebraic handling, we derive the following formula for the density of the gas:

\rho = \frac{P\cdot M}{R_{u}\cdot T} (2)

The gas inside tires has a pressure higher than the pressure outside, but the same temperature usually. Therefore, the density of gas particles inside tires is higher than the density of the gas particles outside.

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Explanation:

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3 years ago
A meter stick balances horizontally on a knife-edge at the 51 cm mark. With two nickels stacked over the 6.0 cm mark, the stick
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65g

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II. The resultant moment must be equal to zero. That is, sum of the moments in one direction about a point must be equal to the sum of the moments in another direction about the same point.

For the above question,

the 51cm mark is the point where the resultant weight of the meter stick lies,

the pivot or point is the 45cm mark where the stick balanced when 2 nickels ( total mass (5.0g x 2) 10g were placed at the 6cm mark.

Using the conversion factor:

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