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eduard
3 years ago
8

How does the density of gas particles inside your tires compare with the density of gas particles in the air outside your tires

Physics
1 answer:
bixtya [17]3 years ago
4 0

Answer:

The density of gas particles inside tires is higher than the density of the gas particles outside.

Explanation:

Let suppose that both gas inside and outside tires behave ideally. The equation of state for ideal gases is presented below:

P\cdot V = n\cdot R_{u}\cdot T (1)

Where:

P - Pressure.

V - Volume.

n - Molar quantity.

R_{u} - Ideal gas constant.

T - Temperature.

By definition of molar quantity, we expand (1) into this form:

P\cdot V = \frac{m\cdot R_{u}\cdot T}{M}

And after some algebraic handling, we derive the following formula for the density of the gas:

\rho = \frac{P\cdot M}{R_{u}\cdot T} (2)

The gas inside tires has a pressure higher than the pressure outside, but the same temperature usually. Therefore, the density of gas particles inside tires is higher than the density of the gas particles outside.

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Answer:

time constant will decrease and steady state current will decrease on increasing the resistance

Explanation:

As we know that the EMF of cell is E which is used to connected across a resistor and an inductor.

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now here we have

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also the steady state current will be smaller in that case

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3 years ago
PLS ANSWERR THIS QUESTION FOR ME !!
MA_775_DIABLO [31]

Explanation:

20 joule is your answer

Answer:

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The maximum force that the athlete exerts on the bag is equal to 1,500 N and in the opposite direction as the force that the bag exerts on the athlete.

<h3>Newton's third law of motion</h3>

Newton's third law of motion states that action and reaction are equal and opposite.

Fa = -Fb

The force exerted by the athlete on the bag is equal to the force the bag exerted on the athlete but in opposite direction.

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Learn more about force here: brainly.com/question/12970081

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