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Soloha48 [4]
2 years ago
15

A cheetah running initially at a velocity of 20 m/s accelerates

Physics
1 answer:
Nesterboy [21]2 years ago
8 0

Answer: I think it’s 32 m/s

Explanation: Vi=20 m/s

Vf=?

a=3.0 m/s^2

t= 4s

Vf= Vi + at

Vf= 20 m/s + (3 m/s^2)(4s)

Vf= 20 m/s + 12m/s

Vf= 32m/s

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A motorboat traveling on a straight course slows
never [62]

Answer:

2.572 m/s²

Explanation:

Convert the given initial velocity and final velocity rates to m/s:

  • 65 km/h → 18.0556 m/s
  • 35 km/h → 9.72222 m/s

The motorboat's displacement is 45 m during this time.

We are trying to find the acceleration of the boat.

We have the variables v₀, v, a, and Δx. Find the constant acceleration equation that contains all four of these variables.

  • v² = v₀² + 2aΔx

Substitute the known values into the equation.

  • (9.72222)² = (18.0556)² + 2a(45)
  • 94.52156173 = 326.0046914 + 90a
  • -231.4831296 = 90a
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The magnitude of the boat's acceleration is |-2.572| = 2.572 m/s².

3 0
3 years ago
The intensity of electromagnetic waves from the sun is 1.4kW/m2 just above the earth's atmosphere. Eighty percent of this reache
Arlecino [84]

Answer:

E=8.02*10^{5}J

Explanation:

Given data

Electromagnetic waves from the sun is I=1.4kW/m² at 80%

Area a=(0.30×0.51)m²

Time t=1.30 hr

To find

Energy E

Solution

The energy received by your back is calculated as:

E=Pt=Iat\\E=(0.80)(1400W/m^{2} )(0.30*0.51m^{2} )(1.30*3600s)\\E=8.02*10^{5}J

3 0
3 years ago
Read 2 more answers
Why don't you feel the pressure exerted by the atmosphere?
mariarad [96]

Answer:

the air within our bodies (in our lungs and stomachs, for example) is exerting the same pressure outwards so there's no pressure difference and no need for us to exert any effort.

Explanation:

8 0
3 years ago
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an experiment was done to see which colored sand would heat up the most when placed in the sun. The sand samples were white, red
olga_2 [115]
•Independent: different color sand samples
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•Control/constant (means the same thing) : Same containers, same time in sun, same thermometer
7 0
3 years ago
A swimmer swims north at 0.10 m/s relative to still water across a river that flows at 0.25 m/s from east to west. Calculate the
ValentinkaMS [17]
0.15 m/s East
If you follow the equation a=vf-vi/t, you'll discover that subtracting the final velocity, 0.25 m/s, by the initial velocity, 0.10 m/s, and divide by zero, (bc there was no given time) the answer is 0.15 m/s East
7 0
3 years ago
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